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If x = 7 4 root 3 and xy = 1 then find one upon X square 1 upon y square?
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If x = 7 4 root 3 and xy = 1 then find one upon X square 1 upon y ...
Given:

  • x = 7√3

  • xy = 1



To find:

  • 1/x² + 1/y²



Solution:

Let's first find the value of y.

Given, xy = 1

Therefore, y = 1/x

Now, substituting the value of x and y in the expression 1/x² + 1/y², we get:

1/x² + 1/y² = (1/(7√3)²) + 1/(1/x)²

1/x² + 1/y² = (1/147) + x²

Now, we need to find the value of x².

Given, x = 7√3

Therefore, x² = (7√3)² = 147

Substituting the value of x² in the expression 1/x² + 1/y², we get:

1/x² + 1/y² = (1/147) + 147

1/x² + 1/y² = (1/147) + (147/1)

1/x² + 1/y² = 148/147


Answer:

1/x² + 1/y² = 148/147
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