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X equals to 7 4 root 3 and xy = 1 then find the value of 1/x square 1 upon y square?
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X equals to 7 4 root 3 and xy = 1 then find the value of 1/x square ...
Solution:

Given that X = 7 + 4√3 and XY = 1.

We have to find the value of 1/X^2 and 1/Y^2.

Step 1: Find the value of Y.

XY = 1

Y = 1/X

Y = 1/(7 + 4√3)

Step 2: Find the value of X^2.

X^2 = (7 + 4√3)^2

X^2 = 49 + 56√3 + 48

X^2 = 97 + 56√3

Step 3: Find the value of Y^2.

Y^2 = (1/X)^2

Y^2 = 1/(7 + 4√3)^2

Y^2 = 1/(49 + 56√3 + 48)

Y^2 = 1/(97 + 56√3)

Step 4: Find the value of 1/X^2 and 1/Y^2.

1/X^2 = 1/(97 + 56√3)

1/Y^2 = 97 + 56√3

Therefore, the value of 1/X^2 is 1/(97 + 56√3) and the value of 1/Y^2 is 97 + 56√3.

Explanation:

We are given X and XY. From XY, we can find the value of Y. Using X and Y, we can find the value of X^2 and Y^2. Finally, we can find the value of 1/X^2 and 1/Y^2.
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