A two digit number is such that the product of its digit is 18. When 6...
A two digit number is such that the product of its digit is 18. When 6...
Analysis:
The given conditions are:
1. The product of the digits is 18.
2. When 63 is subtracted from the number, the digits interchange their places.
Let the two-digit number be represented as 10a + b, where 'a' is the digit in the tens place and 'b' is the digit in the units place.
Step 1: Finding the possible pairs of digits:
Since the product of the digits is 18, we need to find all the possible pairs of digits that multiply to 18. These pairs are (1, 18), (2, 9), and (3, 6).
Step 2: Forming the equations:
Let's assume the number is 10a + b. From the given conditions, we can form the following equations:
1. a * b = 18
2. 10a + b - 63 = 10b + a
Step 3: Solving the equations:
From equation 1, we can find the possible pairs of digits that multiply to 18. The pairs are (a, b) = (2, 9) or (a, b) = (3, 6).
Substitute these pairs in equation 2 and solve for the two-digit number:
For (a, b) = (2, 9):
10(2) + 9 - 63 = 29
For (a, b) = (3, 6):
10(3) + 6 - 63 = 36
Answer:
Therefore, the two-digit number is 36.
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