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 Avogadro’s number is the number of molecules present in
  • a)
    1 litre of molecule 
  • b)
    1 g of molecule
  • c)
    gram molecular mass
  • d)
    1 g atom of molecules
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Avogadro’s number is the number of molecules present ina)1 litre...
Avogadro's Number and Gram Molecular Mass:
Avogadro's number, denoted as \(N_A\), is a fundamental constant in chemistry that represents the number of particles (atoms, molecules, ions, etc.) in one mole of a substance. The value of Avogadro's number is approximately \(6.022 \times 10^{23}\) particles per mole.

Explanation:

Gram Molecular Mass:
- Gram molecular mass is the mass of one mole of a substance in grams. It is numerically equal to the molecular mass of a substance expressed in atomic mass units (amu).
- For example, the gram molecular mass of water (H2O) is 18 g/mol, which means one mole of water weighs 18 grams.

Relationship between Avogadro's Number and Gram Molecular Mass:
- Avogadro's number is the number of particles present in one mole of a substance. Therefore, if we have one mole of a substance with a gram molecular mass, it will contain Avogadro's number of molecules.
- For example, if we have one mole of a substance with a gram molecular mass of 18 g/mol, it will contain approximately \(6.022 \times 10^{23}\) molecules.

Answer:
- In the given question, Avogadro's number is related to the gram molecular mass because one mole of a substance with a specific gram molecular mass will contain Avogadro's number of molecules.
- Therefore, the correct answer is option 'C', gram molecular mass, as Avogadro's number is the number of molecules present in one mole of a substance.
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Community Answer
Avogadro’s number is the number of molecules present ina)1 litre...
Avogadro’s number is 6.023 x 1023 which is equal to molecules present in gram molecular mass.
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Avogadro’s number is the number of molecules present ina)1 litre of moleculeb)1 g of moleculec)gram molecular massd)1 g atom of moleculesCorrect answer is option 'C'. Can you explain this answer?
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