Study the line graph and answer the question that follows.Below the pa...
Correct Option: A
Let, length (in metres) of train A, train B, train C, train D, and train E be ‘a’, ’b’, ‘c’, ‘d’, and ‘e’, respectively.
And, speed (in m/s) of train A, train B, train C, train D, and train E be ‘p’, ‘q’, ‘r’, ‘s’, and ‘t’, respectively.
2 × (a + b + c + d + e) = 3380
⇒2 × (630 + 700 + e) = 3380
⇒e = 360 m
a = 660 – 360 = 300 m
b = 630 – 300 = 330 m
c = 840 – 330 = 510 m
d = 700 – 510 = 190 m
⇒ q + r = 35
Similarly,
r + s = 25
s + t = 40
p + t = 45
So, 2 × (p + q + r + s + t) = 190
⇒p + q + r + s + t = 85
⇒45 + r + 40 = 95
⇒r = 10
So, s = 15, t = 25, p = 20, q = 25
Distance travelled by train A to meet train D = 90 × 5.5 = 495 km (We have multiplied by 5.5 as train A travelled 2 hrs less than train D)
Required distance = 405 + 495 = 900 km
Hence, option A is correct.