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The curve described parametrically by x = t2 + 2t − 1, y = 3t + 5 represents
  • a)
    An ellipse
  • b)
    A hyperbola
  • c)
    A parabola
  • d)
    A circle
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The curve described parametrically byx = t2 + 2t − 1, y = 3t + 5...
Y = t2 + 1is a parabola that opens upwards and has its vertex at (0,1). To see this, we can rewrite the parametric equations as:

x = t(t+2)
y = t2 + 1

Solving for t in terms of x, we get:

t = ( -2 ± √(4x+1) ) / 2

Substituting this expression for t into the equation for y, we obtain:

y = ( -2 ± √(4x+1) ) / 2 + 1

which simplifies to:

y = -1 ± √(4x+1)

This is the equation of a parabola that opens upwards and has its vertex at (0,1), as can be seen from its graph:

![parabola](https://i.imgur.com/59QXvRy.png)
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Community Answer
The curve described parametrically byx = t2 + 2t − 1, y = 3t + 5...
Given, x=t2+2t−1 ...(i)

On putting the value of t in Eq. (i), we get

This is an equation of a parabola
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The curve described parametrically byx = t2 + 2t − 1, y = 3t + 5representsa)An ellipseb)A hyperbolac)A parabolad)A circleCorrect answer is option 'C'. Can you explain this answer?
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