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Two jars ofcapacity 3 and 5 liters are filled with mixtures of alcohol and water.In the smaller jar 25% of the mixture is alcohol and in the larger 25% of the mixture is water. The jars are emptied into a 9 litre cask and remaining volume is filled upwith water.Then percentage of alcohol in the cask will be?
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Two jars ofcapacity 3 and 5 liters are filled with mixtures of alcohol...
Problem Solving: Percentage of Alcohol in the Cask


Given Information:

Two jars of capacity 3 and 5 liters are filled with mixtures of alcohol and water. In the smaller jar, 25% of the mixture is alcohol and in the larger, 25% of the mixture is water. The jars are emptied into a 9-liter cask, and the remaining volume is filled up with water.


Solution:


Step 1: Calculation of Amount of Alcohol in the Jars

To calculate the amount of alcohol in the jars, we need to know the volume of alcohol in each jar.


  • In the smaller jar, 25% of the mixture is alcohol. Therefore, the volume of alcohol in the smaller jar is 0.25 x 3 liters = 0.75 liters.

  • In the larger jar, 25% of the mixture is water. Therefore, the volume of alcohol in the larger jar is 0.75 x 5 liters = 1.25 liters.



Step 2: Calculation of Total Volume of Mixture

The total volume of the mixture in the cask is the sum of the volumes of the mixtures in the two jars.


  • Total volume of mixture = 3 liters + 5 liters = 8 liters



Step 3: Calculation of Percentage of Alcohol in the Cask

The remaining volume in the cask is filled with water, so the total volume of the cask is 9 liters. Therefore, the volume of water in the cask is:


  • Volume of water in the cask = 9 liters - 8 liters = 1 liter


To calculate the percentage of alcohol in the cask, we need to know the total volume of alcohol in the cask.


  • Total volume of alcohol in the cask = 0.75 liters + 1.25 liters = 2 liters


Therefore, the percentage of alcohol in the cask is:


  • Percentage of alcohol in the cask = (Total volume of alcohol / Total volume of mixture) x 100

  • Percentage of alcohol in the cask = (2 liters / 9 liters) x 100 = 22.22%



Answer:

The percentage of alcohol in the cask is 22.22%.
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Two jars ofcapacity 3 and 5 liters are filled with mixtures of alcohol and water.In the smaller jar 25% of the mixture is alcohol and in the larger 25% of the mixture is water. The jars are emptied into a 9 litre cask and remaining volume is filled upwith water.Then percentage of alcohol in the cask will be?
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Two jars ofcapacity 3 and 5 liters are filled with mixtures of alcohol and water.In the smaller jar 25% of the mixture is alcohol and in the larger 25% of the mixture is water. The jars are emptied into a 9 litre cask and remaining volume is filled upwith water.Then percentage of alcohol in the cask will be? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about Two jars ofcapacity 3 and 5 liters are filled with mixtures of alcohol and water.In the smaller jar 25% of the mixture is alcohol and in the larger 25% of the mixture is water. The jars are emptied into a 9 litre cask and remaining volume is filled upwith water.Then percentage of alcohol in the cask will be? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two jars ofcapacity 3 and 5 liters are filled with mixtures of alcohol and water.In the smaller jar 25% of the mixture is alcohol and in the larger 25% of the mixture is water. The jars are emptied into a 9 litre cask and remaining volume is filled upwith water.Then percentage of alcohol in the cask will be?.
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