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How can we prove that diogonals of a rhombus bisect each other at90 Degree?
Most Upvoted Answer
How can we prove that diogonals of a rhombus bisect each other at90 De...
We know that diagonals bisect each other at midpoint. 1 diagonal divides a rhombus into 2 triangles and other diagonal divides 1 both of these triangles into four more triangle. If we see 2 adjacent triangles they both are congruent by SSS method (as the sides are equal and diagonals bisect at midpoint and another side is common in both triangles). Now in 1 diagonal is a straight line and other and another diagonal bisects at midpoint and forms two triangles, they both are congruent. At the point it bisects it divides into two angles of a diagonal which is 180 degree(straight line) and the both angles should be eqaul as the triangles formed are congruent then = 180÷2 = 90 degree each angle.HENCE PROVED that the diagonals bisect at 90 degree
Community Answer
How can we prove that diogonals of a rhombus bisect each other at90 De...
Every llgram is a rhombus and one property of llgram is that the digonal of the llgram bisect each other and digonal of rhombus bisect at 90degrew
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How can we prove that diogonals of a rhombus bisect each other at90 Degree?
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