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What is the output of the following code?
#include <iostream>
using namespace std;
int knapsack(int W, int wt[], int val[], int n) {
    int dp[n+1][W+1];
    for (int i = 0; i <= n; i++) {
        for (int w = 0; w <= W; w++) {
            if (i == 0 || w == 0)
                dp[i][w] = 0;
            else if (wt[i-1] <= w)
                dp[i][w] = max(val[i-1] + dp[i-1][w-wt[i-1]], dp[i-1][w]);
            else
                dp[i][w] = dp[i-1][w];
        }
    }
    return dp[n][W];
}
int main() {
    int val[] = {60, 100, 120};
    int wt[] = {10, 20, 30};
    int W = 50;
    int n = sizeof(val)/sizeof(val[0]);
    cout << knapsack(W, wt, val, n);
    return 0;
}
  • a)
    100
  • b)
    120
  • c)
    220
  • d)
    240
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
What is the output of the following code?#include <iostream>usin...
The code solves the 0-1 Knapsack problem using Dynamic Programming. Given weights and values of items, the knapsack function calculates the maximum value that can be obtained by selecting items with a total weight not exceeding W. In this case, the maximum value that can be obtained is 220.
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What is the output of the following code?#include <iostream>using namespace std;int knapsack(int W, int wt[], int val[], int n) { int dp[n+1][W+1]; for (int i = 0; i <= n; i++) { for (int w = 0; w <= W; w++) { if (i == 0 || w == 0) dp[i][w] = 0; else if (wt[i-1] <= w) dp[i][w] = max(val[i-1] + dp[i-1][w-wt[i-1]], dp[i-1][w]); else dp[i][w] = dp[i-1][w]; } } return dp[n][W];}int main() { int val[] = {60, 100, 120}; int wt[] = {10, 20, 30}; int W = 50; int n = sizeof(val)/sizeof(val[0]); cout << knapsack(W, wt, val, n); return 0;}a)100b)120c)220d)240Correct answer is option 'C'. Can you explain this answer?
Question Description
What is the output of the following code?#include <iostream>using namespace std;int knapsack(int W, int wt[], int val[], int n) { int dp[n+1][W+1]; for (int i = 0; i <= n; i++) { for (int w = 0; w <= W; w++) { if (i == 0 || w == 0) dp[i][w] = 0; else if (wt[i-1] <= w) dp[i][w] = max(val[i-1] + dp[i-1][w-wt[i-1]], dp[i-1][w]); else dp[i][w] = dp[i-1][w]; } } return dp[n][W];}int main() { int val[] = {60, 100, 120}; int wt[] = {10, 20, 30}; int W = 50; int n = sizeof(val)/sizeof(val[0]); cout << knapsack(W, wt, val, n); return 0;}a)100b)120c)220d)240Correct answer is option 'C'. Can you explain this answer? for Software Development 2024 is part of Software Development preparation. The Question and answers have been prepared according to the Software Development exam syllabus. Information about What is the output of the following code?#include <iostream>using namespace std;int knapsack(int W, int wt[], int val[], int n) { int dp[n+1][W+1]; for (int i = 0; i <= n; i++) { for (int w = 0; w <= W; w++) { if (i == 0 || w == 0) dp[i][w] = 0; else if (wt[i-1] <= w) dp[i][w] = max(val[i-1] + dp[i-1][w-wt[i-1]], dp[i-1][w]); else dp[i][w] = dp[i-1][w]; } } return dp[n][W];}int main() { int val[] = {60, 100, 120}; int wt[] = {10, 20, 30}; int W = 50; int n = sizeof(val)/sizeof(val[0]); cout << knapsack(W, wt, val, n); return 0;}a)100b)120c)220d)240Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Software Development 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is the output of the following code?#include <iostream>using namespace std;int knapsack(int W, int wt[], int val[], int n) { int dp[n+1][W+1]; for (int i = 0; i <= n; i++) { for (int w = 0; w <= W; w++) { if (i == 0 || w == 0) dp[i][w] = 0; else if (wt[i-1] <= w) dp[i][w] = max(val[i-1] + dp[i-1][w-wt[i-1]], dp[i-1][w]); else dp[i][w] = dp[i-1][w]; } } return dp[n][W];}int main() { int val[] = {60, 100, 120}; int wt[] = {10, 20, 30}; int W = 50; int n = sizeof(val)/sizeof(val[0]); cout << knapsack(W, wt, val, n); return 0;}a)100b)120c)220d)240Correct answer is option 'C'. Can you explain this answer?.
Solutions for What is the output of the following code?#include <iostream>using namespace std;int knapsack(int W, int wt[], int val[], int n) { int dp[n+1][W+1]; for (int i = 0; i <= n; i++) { for (int w = 0; w <= W; w++) { if (i == 0 || w == 0) dp[i][w] = 0; else if (wt[i-1] <= w) dp[i][w] = max(val[i-1] + dp[i-1][w-wt[i-1]], dp[i-1][w]); else dp[i][w] = dp[i-1][w]; } } return dp[n][W];}int main() { int val[] = {60, 100, 120}; int wt[] = {10, 20, 30}; int W = 50; int n = sizeof(val)/sizeof(val[0]); cout << knapsack(W, wt, val, n); return 0;}a)100b)120c)220d)240Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Software Development. Download more important topics, notes, lectures and mock test series for Software Development Exam by signing up for free.
Here you can find the meaning of What is the output of the following code?#include <iostream>using namespace std;int knapsack(int W, int wt[], int val[], int n) { int dp[n+1][W+1]; for (int i = 0; i <= n; i++) { for (int w = 0; w <= W; w++) { if (i == 0 || w == 0) dp[i][w] = 0; else if (wt[i-1] <= w) dp[i][w] = max(val[i-1] + dp[i-1][w-wt[i-1]], dp[i-1][w]); else dp[i][w] = dp[i-1][w]; } } return dp[n][W];}int main() { int val[] = {60, 100, 120}; int wt[] = {10, 20, 30}; int W = 50; int n = sizeof(val)/sizeof(val[0]); cout << knapsack(W, wt, val, n); return 0;}a)100b)120c)220d)240Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of What is the output of the following code?#include <iostream>using namespace std;int knapsack(int W, int wt[], int val[], int n) { int dp[n+1][W+1]; for (int i = 0; i <= n; i++) { for (int w = 0; w <= W; w++) { if (i == 0 || w == 0) dp[i][w] = 0; else if (wt[i-1] <= w) dp[i][w] = max(val[i-1] + dp[i-1][w-wt[i-1]], dp[i-1][w]); else dp[i][w] = dp[i-1][w]; } } return dp[n][W];}int main() { int val[] = {60, 100, 120}; int wt[] = {10, 20, 30}; int W = 50; int n = sizeof(val)/sizeof(val[0]); cout << knapsack(W, wt, val, n); return 0;}a)100b)120c)220d)240Correct answer is option 'C'. Can you explain this answer?, a detailed solution for What is the output of the following code?#include <iostream>using namespace std;int knapsack(int W, int wt[], int val[], int n) { int dp[n+1][W+1]; for (int i = 0; i <= n; i++) { for (int w = 0; w <= W; w++) { if (i == 0 || w == 0) dp[i][w] = 0; else if (wt[i-1] <= w) dp[i][w] = max(val[i-1] + dp[i-1][w-wt[i-1]], dp[i-1][w]); else dp[i][w] = dp[i-1][w]; } } return dp[n][W];}int main() { int val[] = {60, 100, 120}; int wt[] = {10, 20, 30}; int W = 50; int n = sizeof(val)/sizeof(val[0]); cout << knapsack(W, wt, val, n); return 0;}a)100b)120c)220d)240Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of What is the output of the following code?#include <iostream>using namespace std;int knapsack(int W, int wt[], int val[], int n) { int dp[n+1][W+1]; for (int i = 0; i <= n; i++) { for (int w = 0; w <= W; w++) { if (i == 0 || w == 0) dp[i][w] = 0; else if (wt[i-1] <= w) dp[i][w] = max(val[i-1] + dp[i-1][w-wt[i-1]], dp[i-1][w]); else dp[i][w] = dp[i-1][w]; } } return dp[n][W];}int main() { int val[] = {60, 100, 120}; int wt[] = {10, 20, 30}; int W = 50; int n = sizeof(val)/sizeof(val[0]); cout << knapsack(W, wt, val, n); return 0;}a)100b)120c)220d)240Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice What is the output of the following code?#include <iostream>using namespace std;int knapsack(int W, int wt[], int val[], int n) { int dp[n+1][W+1]; for (int i = 0; i <= n; i++) { for (int w = 0; w <= W; w++) { if (i == 0 || w == 0) dp[i][w] = 0; else if (wt[i-1] <= w) dp[i][w] = max(val[i-1] + dp[i-1][w-wt[i-1]], dp[i-1][w]); else dp[i][w] = dp[i-1][w]; } } return dp[n][W];}int main() { int val[] = {60, 100, 120}; int wt[] = {10, 20, 30}; int W = 50; int n = sizeof(val)/sizeof(val[0]); cout << knapsack(W, wt, val, n); return 0;}a)100b)120c)220d)240Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice Software Development tests.
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