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A source of emf E = 15V and having negligible internal resistance, is connected to a variable resistance, so that the current in the circuit increases with time as I = 1.2 t + 3. Then, the total charge that will flow in first 5s will be-
  • a)
    10C
  • b)
    20C
  • c)
    30C
  • d)
    40C
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A source of emf E = 15V and having negligible internal resistance, is ...
Given:
I = 1.2t + 3
Charge (q) is given by q = ∫ Idt
Integrating the expression using
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Community Answer
A source of emf E = 15V and having negligible internal resistance, is ...
Given Information:
- Emf of the source, E = 15V
- Internal resistance, r = 0 (negligible)
- Current in the circuit, I = 1.2t + 3
- Time duration, t = 5s

Calculating total charge flow:
- To find the total charge that will flow in the first 5 seconds, we need to calculate the total charge Q using the formula:
Q = ∫Idt
- Given I = 1.2t + 3
- Integrating I with respect to time from 0 to 5 seconds:
Q = ∫(1.2t + 3)dt
Q = [0.6t^2 + 3t] from 0 to 5
Q = (0.6*5^2 + 3*5) - (0.6*0^2 + 3*0)
Q = (15 + 15) - 0
Q = 30C
Therefore, the total charge that will flow in the first 5 seconds is 30C, which corresponds to option 'C'.
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A source of emf E = 15V and having negligible internal resistance, is connected to a variable resistance, so that the current in the circuit increases with time as I = 1.2 t + 3. Then, the total charge that will flow in first 5s will be-a)10Cb)20Cc)30Cd)40CCorrect answer is option 'C'. Can you explain this answer?
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