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A metal crystalizes in fcc structure with unit cell side of 500pm. if the density of crystal is 1.33g/cc, the molar mass of the metal is closed to?


A. 23
B. 24
C. 25
D. 26?
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A metal crystalizes in fcc structure with unit cell side of 500pm. if ...
Answer:

Given:

Unit cell side (a) = 500 pm = 500 x 10^-12 m

Density (ρ) = 1.33 g/cc = 1.33 x 10^3 kg/m^3

Formula:

Density (ρ) = (Z x M) / (a^3 x N_A)

Where,

Z = Number of atoms per unit cell

M = Molar mass of the metal

a = Unit cell side

N_A = Avogadro's number (6.022 x 10^23)

Calculation:

Since the given metal crystalizes in fcc structure,

Number of atoms per unit cell (Z) = 4

Volume of unit cell (V) = a^3

Atomic radius (r) = (sqrt(2) / 2) x a

Molar volume (V_m) = (Z x V) / N_A = (4 x a^3) / (6.022 x 10^23) = 4.16 x 10^-29 m^3

Molar mass (M) = Density (ρ) x Molar volume (V_m) = 1.33 x 10^3 kg/m^3 x 4.16 x 10^-29 m^3 = 5.53 x 10^-26 kg


Converting kg to g and calculating the molar mass,

Molar mass (M) = 5.53 x 10^-26 kg x 1000 g/kg / (6.022 x 10^23) = 9.2 g/mol

Answer:

The molar mass of the metal is closed to 9.2 g/mol.
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A metal crystalizes in fcc structure with unit cell side of 500pm. if ...
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A metal crystalizes in fcc structure with unit cell side of 500pm. if the density of crystal is 1.33g/cc, the molar mass of the metal is closed to? A. 23B. 24C. 25D. 26?
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