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Two elements, A and B, form compounds having molecular formulae AB2 and AB4 when dissolved in 20g of C6H6, 1.0g AB2 lowers the freezing point by 2.3K whereas 1.0g of AB4 lowers it by 1.3K. The molal depression freezing point constant for benzene is 5.1 kg mol-1. The atomic masses of A and B (in g mol-1) respectively are (assume AB2 and AB4 are non-ionisable)
- a)A=26; B=42.64
- b)A=31.72; B=47.02
- c)A=13.11; B=24.25
- d)A=19.17; B=35.01
Correct answer is option 'A'. Can you explain this answer?
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Two elements, A and B,form compounds having molecular formulae AB2and ...
Suppose, the atomic masses of A and B are x and y respectively.
Molar mass of AB2 = x + 2y
Similarly, for the 2nd case,
Solving equations (i) and (ii), we get,
x=25.69; y=42.64
Therefore, A = 26 and B =42.64
Molar mass of AB2 = x + 2y
Similarly, for the 2nd case,
Solving equations (i) and (ii), we get,
x=25.69; y=42.64
Therefore, A = 26 and B =42.64
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Two elements, A and B,form compounds having molecular formulae AB2and AB4when dissolved in 20g of C6H6, 1.0g AB2 lowers the freezing point by2.3Kwhereas 1.0g of AB4 lowers it by 1.3K. Themolal depression freezing point constant for benzene is 5.1 kg mol-1.The atomic masses of A and B (in g mol-1)respectively are(assume AB2 and AB4are non-ionisable)a)A=26; B=42.64b)A=31.72; B=47.02c)A=13.11; B=24.25d)A=19.17; B=35.01Correct answer is option 'A'. Can you explain this answer?
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Two elements, A and B,form compounds having molecular formulae AB2and AB4when dissolved in 20g of C6H6, 1.0g AB2 lowers the freezing point by2.3Kwhereas 1.0g of AB4 lowers it by 1.3K. Themolal depression freezing point constant for benzene is 5.1 kg mol-1.The atomic masses of A and B (in g mol-1)respectively are(assume AB2 and AB4are non-ionisable)a)A=26; B=42.64b)A=31.72; B=47.02c)A=13.11; B=24.25d)A=19.17; B=35.01Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two elements, A and B,form compounds having molecular formulae AB2and AB4when dissolved in 20g of C6H6, 1.0g AB2 lowers the freezing point by2.3Kwhereas 1.0g of AB4 lowers it by 1.3K. Themolal depression freezing point constant for benzene is 5.1 kg mol-1.The atomic masses of A and B (in g mol-1)respectively are(assume AB2 and AB4are non-ionisable)a)A=26; B=42.64b)A=31.72; B=47.02c)A=13.11; B=24.25d)A=19.17; B=35.01Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two elements, A and B,form compounds having molecular formulae AB2and AB4when dissolved in 20g of C6H6, 1.0g AB2 lowers the freezing point by2.3Kwhereas 1.0g of AB4 lowers it by 1.3K. Themolal depression freezing point constant for benzene is 5.1 kg mol-1.The atomic masses of A and B (in g mol-1)respectively are(assume AB2 and AB4are non-ionisable)a)A=26; B=42.64b)A=31.72; B=47.02c)A=13.11; B=24.25d)A=19.17; B=35.01Correct answer is option 'A'. Can you explain this answer?.
Two elements, A and B,form compounds having molecular formulae AB2and AB4when dissolved in 20g of C6H6, 1.0g AB2 lowers the freezing point by2.3Kwhereas 1.0g of AB4 lowers it by 1.3K. Themolal depression freezing point constant for benzene is 5.1 kg mol-1.The atomic masses of A and B (in g mol-1)respectively are(assume AB2 and AB4are non-ionisable)a)A=26; B=42.64b)A=31.72; B=47.02c)A=13.11; B=24.25d)A=19.17; B=35.01Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two elements, A and B,form compounds having molecular formulae AB2and AB4when dissolved in 20g of C6H6, 1.0g AB2 lowers the freezing point by2.3Kwhereas 1.0g of AB4 lowers it by 1.3K. Themolal depression freezing point constant for benzene is 5.1 kg mol-1.The atomic masses of A and B (in g mol-1)respectively are(assume AB2 and AB4are non-ionisable)a)A=26; B=42.64b)A=31.72; B=47.02c)A=13.11; B=24.25d)A=19.17; B=35.01Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two elements, A and B,form compounds having molecular formulae AB2and AB4when dissolved in 20g of C6H6, 1.0g AB2 lowers the freezing point by2.3Kwhereas 1.0g of AB4 lowers it by 1.3K. Themolal depression freezing point constant for benzene is 5.1 kg mol-1.The atomic masses of A and B (in g mol-1)respectively are(assume AB2 and AB4are non-ionisable)a)A=26; B=42.64b)A=31.72; B=47.02c)A=13.11; B=24.25d)A=19.17; B=35.01Correct answer is option 'A'. Can you explain this answer?.
Solutions for Two elements, A and B,form compounds having molecular formulae AB2and AB4when dissolved in 20g of C6H6, 1.0g AB2 lowers the freezing point by2.3Kwhereas 1.0g of AB4 lowers it by 1.3K. Themolal depression freezing point constant for benzene is 5.1 kg mol-1.The atomic masses of A and B (in g mol-1)respectively are(assume AB2 and AB4are non-ionisable)a)A=26; B=42.64b)A=31.72; B=47.02c)A=13.11; B=24.25d)A=19.17; B=35.01Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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Here you can find the meaning of Two elements, A and B,form compounds having molecular formulae AB2and AB4when dissolved in 20g of C6H6, 1.0g AB2 lowers the freezing point by2.3Kwhereas 1.0g of AB4 lowers it by 1.3K. Themolal depression freezing point constant for benzene is 5.1 kg mol-1.The atomic masses of A and B (in g mol-1)respectively are(assume AB2 and AB4are non-ionisable)a)A=26; B=42.64b)A=31.72; B=47.02c)A=13.11; B=24.25d)A=19.17; B=35.01Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Two elements, A and B,form compounds having molecular formulae AB2and AB4when dissolved in 20g of C6H6, 1.0g AB2 lowers the freezing point by2.3Kwhereas 1.0g of AB4 lowers it by 1.3K. Themolal depression freezing point constant for benzene is 5.1 kg mol-1.The atomic masses of A and B (in g mol-1)respectively are(assume AB2 and AB4are non-ionisable)a)A=26; B=42.64b)A=31.72; B=47.02c)A=13.11; B=24.25d)A=19.17; B=35.01Correct answer is option 'A'. Can you explain this answer?, a detailed solution for Two elements, A and B,form compounds having molecular formulae AB2and AB4when dissolved in 20g of C6H6, 1.0g AB2 lowers the freezing point by2.3Kwhereas 1.0g of AB4 lowers it by 1.3K. Themolal depression freezing point constant for benzene is 5.1 kg mol-1.The atomic masses of A and B (in g mol-1)respectively are(assume AB2 and AB4are non-ionisable)a)A=26; B=42.64b)A=31.72; B=47.02c)A=13.11; B=24.25d)A=19.17; B=35.01Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of Two elements, A and B,form compounds having molecular formulae AB2and AB4when dissolved in 20g of C6H6, 1.0g AB2 lowers the freezing point by2.3Kwhereas 1.0g of AB4 lowers it by 1.3K. Themolal depression freezing point constant for benzene is 5.1 kg mol-1.The atomic masses of A and B (in g mol-1)respectively are(assume AB2 and AB4are non-ionisable)a)A=26; B=42.64b)A=31.72; B=47.02c)A=13.11; B=24.25d)A=19.17; B=35.01Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Two elements, A and B,form compounds having molecular formulae AB2and AB4when dissolved in 20g of C6H6, 1.0g AB2 lowers the freezing point by2.3Kwhereas 1.0g of AB4 lowers it by 1.3K. Themolal depression freezing point constant for benzene is 5.1 kg mol-1.The atomic masses of A and B (in g mol-1)respectively are(assume AB2 and AB4are non-ionisable)a)A=26; B=42.64b)A=31.72; B=47.02c)A=13.11; B=24.25d)A=19.17; B=35.01Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.
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