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What do we get after factorising x+ 6x - 27?
  • a)
    (x + 9)(x - 3)
  • b)
    (x - 9)(x + 3)
  • c)
    (x - 9)(x - 3)
  • d)
    (x + 9)(x + 3)
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
What do we get after factorising x2+ 6x - 27?a)(x + 9)(x - 3)b)(x - 9)...
To factorise x+ 6x - 27, we have to find two numbers ‘a’ and ‘b’ such that a + b = 6 and a * b = 27.
For that we have to find factors of -27, which are ±1, ±3, ±9.
Now we have to arrange two numbers from these numbers such that a + b = 6 and a * b = 27.
By considering this, we get two numbers +9 and -3
9 + (-3) = 6 and 9*-3 = -27
Now after manipulating terms, we get x+ 9x - 3x - 27.
x+ 9x - 3x - 27 = x(x + 9) - 3(x + 9)
= (x + 9)(x - 3).
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Most Upvoted Answer
What do we get after factorising x2+ 6x - 27?a)(x + 9)(x - 3)b)(x - 9)...
To factorise x+ 6x - 27, we have to find two numbers ‘a’ and ‘b’ such that a + b = 6 and a * b = 27.
For that we have to find factors of -27, which are ±1, ±3, ±9.
Now we have to arrange two numbers from these numbers such that a + b = 6 and a * b = 27.
By considering this, we get two numbers +9 and -3
9 + (-3) = 6 and 9*-3 = -27
Now after manipulating terms, we get x+ 9x - 3x - 27.
x+ 9x - 3x - 27 = x(x + 9) - 3(x + 9)
= (x + 9)(x - 3).
Free Test
Community Answer
What do we get after factorising x2+ 6x - 27?a)(x + 9)(x - 3)b)(x - 9)...
To factorise x+ 6x - 27, we have to find two numbers ‘a’ and ‘b’ such that a + b = 6 and a * b = 27.
For that we have to find factors of -27, which are ±1, ±3, ±9.
Now we have to arrange two numbers from these numbers such that a + b = 6 and a * b = 27.
By considering this, we get two numbers +9 and -3
9 + (-3) = 6 and 9*-3 = -27
Now after manipulating terms, we get x+ 9x - 3x - 27.
x+ 9x - 3x - 27 = x(x + 9) - 3(x + 9)
= (x + 9)(x - 3).
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Question Description
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