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ACT Exam  >  ACT Questions  >  What do we get after factorising x2+ 6x - 27?... Start Learning for Free
What do we get after factorising x2 + 6x - 27?
  • a)
    (x + 9)(x - 3)
  • b)
    (x - 9)(x + 3)
  • c)
    (x - 9)(x - 3)
  • d)
    (x + 9)(x + 3)
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
What do we get after factorising x2+ 6x - 27?a)(x + 9)(x - 3)b)(x - 9)...
To factorise x2 + 6x - 27, we have to find two numbers ‘a’ and ‘b’ such that a + b = 6 and a * b = 27.
For that we have to find factors of -27, which are ±1, ±3, ±9.
Now we have to arrange two numbers from these numbers such that a + b = 6 and a * b = 27.
By considering this, we get two numbers +9 and -3
9 + (-3) = 6 and 9*-3 = -27
Now after manipulating terms, we get x2 + 9x - 3x - 27.
x2 + 9x - 3x - 27 = x(x + 9) - 3(x + 9)
= (x + 9)(x - 3).
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Most Upvoted Answer
What do we get after factorising x2+ 6x - 27?a)(x + 9)(x - 3)b)(x - 9)...
Factorising x^2 + 6x - 27:
To factorise the given quadratic equation x^2 + 6x - 27, we need to find two numbers that multiply to the constant term (-27) and add up to the coefficient of the middle term (6). In this case, the numbers are 9 and -3.

Steps to factorise:
- Write the quadratic equation in the form ax^2 + bx + c.
- Identify the values of a, b, and c in the equation.
- Find two numbers that multiply to ac and add up to b.
- Rewrite the middle term using these two numbers.
- Factorise the expression by grouping.

Factorisation:
x^2 + 6x - 27 = x^2 + 9x - 3x - 27
= x(x + 9) - 3(x + 9)
= (x - 3)(x + 9)
Therefore, after factorising x^2 + 6x - 27, we get (x - 3)(x + 9) as the correct answer, which corresponds to option A.
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Community Answer
What do we get after factorising x2+ 6x - 27?a)(x + 9)(x - 3)b)(x - 9)...
To factorise x2 + 6x - 27, we have to find two numbers ‘a’ and ‘b’ such that a + b = 6 and a * b = 27.
For that we have to find factors of -27, which are ±1, ±3, ±9.
Now we have to arrange two numbers from these numbers such that a + b = 6 and a * b = 27.
By considering this, we get two numbers +9 and -3
9 + (-3) = 6 and 9*-3 = -27
Now after manipulating terms, we get x2 + 9x - 3x - 27.
x2 + 9x - 3x - 27 = x(x + 9) - 3(x + 9)
= (x + 9)(x - 3).
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