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What do we get after expanding (p + 3q - 2z)2?
  • a)
    p2 + 9q2 + 4z2 + 6pq – 12qz + 4zp
  • b)
    p2 + 9q2 + 4z2 + 12pq + 12qz + 4zp
  • c)
    p2 + 9q2 + 4z2 – 12pq – 12qz – 4zp
  • d)
    p2 + 9q2 + 4z2 + 6pq – 12qz – 4zp
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
What do we get after expanding (p + 3q - 2z)2?a)p2+ 9q2+ 4z2+ 6pq &nda...
To expand the expression (p + 3q - 2z)^2, we use the formula for expanding a binomial square:

(a + b)^2 = a^2 + 2ab + b^2

In this case, a = p and b = 3q - 2z. So, we have:

(p + 3q - 2z)^2 = p^2 + 2(p)(3q - 2z) + (3q - 2z)^2

Expanding the second term:

2(p)(3q - 2z) = 6pq - 4pz

Expanding the third term:

(3q - 2z)^2 = (3q)^2 - 2(3q)(2z) + (2z)^2
= 9q^2 - 12qz + 4z^2

Putting it all together, we get:

(p + 3q - 2z)^2 = p^2 + 6pq - 4pz + 9q^2 - 12qz + 4z^2

So, the expanded expression is:

p^2 + 6pq - 4pz + 9q^2 - 12qz + 4z^2
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Community Answer
What do we get after expanding (p + 3q - 2z)2?a)p2+ 9q2+ 4z2+ 6pq &nda...
We know that (a+b+c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
(p + 3q - 2z)2can also be written as (p + 3q + (-2z))2.
Here, a = p, b = 3q and c = -2z
Therefore, using that formula we get (p + 3q + (-2z))2
= p2 + (3q)2 + (-2z)2 + 2(p)(3q) + 2(3q)(-2z) + 2(-2z)(p)
= p2 + 9q2 + 4z2 + 6pq – 12qz – 4zp.
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What do we get after expanding (p + 3q - 2z)2?a)p2+ 9q2+ 4z2+ 6pq – 12qz + 4zpb)p2+ 9q2+ 4z2+ 12pq + 12qz + 4zpc)p2+ 9q2+ 4z2– 12pq – 12qz – 4zpd)p2+ 9q2+ 4z2+ 6pq – 12qz – 4zpCorrect answer is option 'D'. Can you explain this answer?
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