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A body is moving with a constant acceleration of 11î + 2ĵ, starting from î + ĵ. What will be the position of the body after 10s?
  • a)
    551î + 101ĵ
  • b)
    550î + 100ĵ
  • c)
    100î – 550ĵ
  • d)
    550î – 550ĵ
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A body is moving with a constant acceleration of 11î + 2, starti...
The body’s displacement is given by s = (1/2)at2. Therefore, after putting in the values, we get, s = (1/2)(11î + 2ĵ)*102 = 550î + 100ĵ. The body initially starts from î + ĵ. Hence, the final position is = initial position + displacement = 551î + 101ĵ.
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A body is moving with a constant acceleration of 11î + 2, starting from î + . What will be the position of the body after 10s?a)551î + 101b)550î + 100c)100î – 550d)550î – 550Correct answer is option 'A'. Can you explain this answer?
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