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Velocity of a man is 25 units in the positive X direction and 75 units in negative Y direction starting from the origin. Velocity of a woman is 25 units in the positive Y direction and 75 units in the negative X direction starting from the origin. What is the relative velocity of the man with respect to the woman?
  • a)
    100î – 100ĵ
  • b)
    100î + 100ĵ
  • c)
    -100î – 100ĵ
  • d)
    0î + 0ĵ
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Velocity of a man is 25 units in the positive X direction and 75 units...
The velocity of the man is 25î – 75ĵ and that of the woman is -75î + 25ĵ. Relative velocity = velocity of man – velocity of woman = 100î – 100ĵ.
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Velocity of a man is 25 units in the positive X direction and 75 units...
Relative Velocity Calculation:
- The velocity of the man (M) with respect to the woman (W) can be calculated by subtracting the velocity of the woman from the velocity of the man.
- Given that the velocity of the man (M) is 25 units in the positive X direction and 75 units in the negative Y direction, represented as M = 25î - 75ĵ.
- The velocity of the woman (W) is 25 units in the positive Y direction and 75 units in the negative X direction, represented as W = -75î + 25ĵ.
- Subtracting the velocity of the woman from the velocity of the man, we get the relative velocity of the man with respect to the woman as M - W = (25î - 75ĵ) - (-75î + 25ĵ) = 25î - 75ĵ + 75î - 25ĵ = 100î - 100ĵ.
- Therefore, the relative velocity of the man with respect to the woman is 100î - 100ĵ, which corresponds to option 'A'.
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A physicist performs a series of experiments to determine the relative magnitude of electric charge on four particles. A given particle is considered to have a higher magnitude of charge than another if it will push out (or draw in) a positive test charge farther than the other particle.A particle that pushes the test charge has positive charge, while a particle that pulls (or draws in) the test charge has negative charge. This is known as the sign of the charge. Magnitude of charge is unrelated to sign.The experiment is conducted on a horizontal axis that measures from 20m in total: from –10m on the left to +10m on the right, with a measurement of 0m in the middle.Experiment 1Particle A is placed at position –5m on the horizontal axis. The test charge has a specific magnitude of charge and is located at +3m on that same axis. The result of the experiment is that the test charge is displaced to +7.5m.Experiment 2Particle B is placed at position –8m on the horizontal axis. The test charge has the same magnitude of charge as the previous experiment and is located at 0m on that same axis. The result of the experiment is that the test charge is displaced to –7.5m.Experiment 3Particle C is placed at position 0m on the horizontal axis. The test charge has the same magnitude of charge as the previous experiment and is located at +8m on that same axis. The result of the experiment is that the test charge is displaced to +10m.Experiment 4Particle D is placed at position –5.5m on the horizontal axis. The test charge has the same magnitude of charge as the previous experiment and is located at +2.5m on that same axis. The result of the experiment is that the test charge is displaced to +7.5m.Q.If particle C and particle D are placed on the axis at the same time, accoring to the results of the experiment, what is likely to occur?

A physicist performs a series of experiments to determine the relative magnitude of electric charge on four particles. A given particle is considered to have a higher magnitude of charge than another if it will push out (or draw in) a positive test charge farther than the other particle.A particle that pushes the test charge has positive charge, while a particle that pulls (or draws in) the test charge has negative charge. This is known as the sign of the charge. Magnitude of charge is unrelated to sign.The experiment is conducted on a horizontal axis that measures from 20m in total: from –10m on the left to +10m on the right, with a measurement of 0m in the middle.Experiment 1Particle A is placed at position –5m on the horizontal axis. The test charge has a specific magnitude of charge and is located at +3m on that same axis. The result of the experiment is that the test charge is displaced to +7.5m.Experiment 2Particle B is placed at position –8m on the horizontal axis. The test charge has the same magnitude of charge as the previous experiment and is located at 0m on that same axis. The result of the experiment is that the test charge is displaced to –7.5m.Experiment 3Particle C is placed at position 0m on the horizontal axis. The test charge has the same magnitude of charge as the previous experiment and is located at +8m on that same axis. The result of the experiment is that the test charge is displaced to +10m.Experiment 4Particle D is placed at position –5.5m on the horizontal axis. The test charge has the same magnitude of charge as the previous experiment and is located at +2.5m on that same axis. The result of the experiment is that the test charge is displaced to +7.5m.Q. Which of the particles is negatively charged?

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Velocity of a man is 25 units in the positive X direction and 75 units in negative Y direction starting from the origin. Velocity of a woman is 25 units in the positive Y direction and 75 units in the negative X direction starting from the origin. What is the relative velocity of the man with respect to the woman?a)100î – 100b)100î + 100c)-100î – 100d)0î + 0Correct answer is option 'A'. Can you explain this answer?
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