x - 1 is a factor of 4x2- 9x - 6.a)Trueb)FalseCorrect answer is option...
According to factor theorem, x - a is a factor of p(x) if p(a) = 0.
Therefore x-1 is a factor of 4x2 - 9x - 6 is a factor if p(1) = 0.
p(1) = 4(1)2 - 9(1) - 6 = 4 – 9 – 6
= -11 ≠ 0
Therefore, we can say that x - 1 is not a factor of 4x2 - 9x - 6.
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x - 1 is a factor of 4x2- 9x - 6.a)Trueb)FalseCorrect answer is option...
According to factor theorem, x - a is a factor of p(x) if p(a) = 0.
Therefore x-1 is a factor of 4x2 - 9x - 6 is a factor if p(1) = 0.
p(1) = 4(1)2 - 9(1) - 6 = 4 – 9 – 6
= -11 ≠ 0
Therefore, we can say that x - 1 is not a factor of 4x2 - 9x - 6.
x - 1 is a factor of 4x2- 9x - 6.a)Trueb)FalseCorrect answer is option...
Statement: x - 1 is a factor of 4x^2 - 9x - 6.
To determine whether x - 1 is a factor of the given quadratic expression, we need to check if the expression is divisible by x - 1. If it is, then x - 1 is a factor; otherwise, it is not a factor.
Division Method:
Step 1: Write the given expression in the form of (x - 1) * quotient + remainder.
4x^2 - 9x - 6 = (x - 1) * (4x + a) + b
Step 2: Equate the coefficients of like terms on both sides of the equation.
For the x^2 term: 4x^2 = x * (4x + a)
This gives us a = 0.
For the x term: -9x = -1 * (4x + a) + b
Simplifying, we get -9x = -4x - b - a
Since a = 0, the equation becomes -9x = -4x - b.
This gives us b = -5x.
For the constant term: -6 = -1 * b
Substituting the value of b, we get -6 = 5x.
Step 3: Solve the equation obtained in the previous step.
-6 = 5x
Dividing both sides by 5, we get x = -6/5.
Conclusion:
Since the remainder is not zero when dividing the given quadratic expression by x - 1, x - 1 is not a factor of 4x^2 - 9x - 6. Therefore, the correct answer is option 'B' (False).