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If log 2= 0.30103, then find the number of digits in 4^50?
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If log 2= 0.30103, then find the number of digits in 4^50?
Explanation:
We know that log (a^b) = b log a
Therefore, log 4^50 = 50 log 4

Finding log 4:
log 4 = log (2^2)
log 4 = 2 log 2
log 4 = 2 x 0.30103
log 4 = 0.60206

Substituting values:
log 4^50 = 50 log 4
log 4^50 = 50 x 0.60206
log 4^50 = 30.103

Finding the number of digits in 4^50:
Number of digits in a number N = floor(log N) + 1
Therefore, number of digits in 4^50 = floor(log 4^50) + 1

Substituting values:
floor(log 4^50) = floor(30.103) = 30
Number of digits in 4^50 = floor(log 4^50) + 1 = 30 + 1 = 31

Conclusion:
The number of digits in 4^50 is 31.
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If log 2= 0.30103, then find the number of digits in 4^50?
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If log 2= 0.30103, then find the number of digits in 4^50? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about If log 2= 0.30103, then find the number of digits in 4^50? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If log 2= 0.30103, then find the number of digits in 4^50?.
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