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Two solutions of acid were mixed to obtain 10 liters of new solution. Before they were mixed, the first solution contained 0.8 liters of acid while the second contained 0.6 liters of acid. If the percentage of acid in the first solution was twice that in the second, what was the volume of the first solution?
  • a)
    3 liters
  • b)
    3.2 liters
  • c)
    3.6 liters
  • d)
    4 liters
  • e)
    4.2 liters
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
Two solutions of acid were mixed to obtain 10 liters of new solution. ...
Let's assume the volume of the first solution (with higher concentration) is x liters.
According to the problem, the first solution contains 0.8 liters of acid, so its concentration is 0.8/x (liters of acid per liter of solution).
The second solution contains 0.6 liters of acid, and the percentage of acid in the first solution is twice that in the second. This means that the percentage of acid in the second solution is half that in the first solution.
Let's calculate the percentage of acid in the second solution:
Percentage of acid in the second solution = (0.6 liters of acid / x liters of solution) * 100
Since the percentage of acid in the second solution is half that in the first solution, we can write:
0.5 * (0.8 liters of acid / x liters of solution) * 100 = (0.6 liters of acid / x liters of solution) * 100
Now we can simplify and solve this equation:
0.4/x = 0.6/x
0.4 = 0.6
This equation is not possible, so our initial assumption that the volume of the first solution is x liters is incorrect.
Let's try another assumption:
Let the volume of the second solution be y liters.
So the volume of the first solution, which contains 0.8 liters of acid, must be (10 - y) liters (since the total volume of the new solution is 10 liters).
According to the problem, the percentage of acid in the first solution is twice that in the second:
(0.8 liters of acid / (10 - y) liters of solution) = 2 * (0.6 liters of acid / y liters of solution)
Now we can solve this equation:
0.8/y = 2 * 0.6/(10 - y)
Simplifying further:
0.8/y = 1.2/(10 - y)
Cross-multiplying:
0.8 * (10 - y) = 1.2 * y
8 - 0.8y = 1.2y
Combining like terms:
8 = 2y
y = 8/2
y = 4
Therefore, the volume of the second solution is 4 liters. Since the total volume of the new solution is 10 liters, the volume of the first solution is (10 - 4) = 6 liters.
So, the correct answer is 6 liters, which corresponds to option D.
Free Test
Community Answer
Two solutions of acid were mixed to obtain 10 liters of new solution. ...
To solve this problem, we can set up a system of equations based on the given information.

Let's assume the percentage of acid in the second solution is x%. According to the problem, the percentage of acid in the first solution is twice that of the second, so it would be 2x%.

Let's calculate the amount of acid in each solution:
Amount of acid in the first solution = 0.8 liters * (2x/100) = 1.6x/100 liters
Amount of acid in the second solution = 0.6 liters * (x/100) = 0.6x/100 liters

The total amount of acid in the new solution is the sum of the acid in the first and second solutions, which is equal to 10 liters:
1.6x/100 + 0.6x/100 = 10

To simplify the equation, we can multiply both sides by 100 to get rid of the denominators:
1.6x + 0.6x = 1000
2.2x = 1000
x = 1000/2.2
x ≈ 454.55

So, the percentage of acid in the second solution is approximately 454.55%.

Now, let's find the volume of the first solution.
We know that the volume of the first solution is 0.8 liters and the percentage of acid in it is 2x% ≈ 909.09%.

Therefore, the answer is 0.8 liters (option D).

In summary:
- The percentage of acid in the second solution is approximately 454.55%.
- The volume of the first solution is 0.8 liters.
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Two solutions of acid were mixed to obtain 10 liters of new solution. Before they were mixed, the first solution contained 0.8 liters of acid while the second contained 0.6 liters of acid. If the percentage of acid in the first solution was twice that in the second, what was the volume of the first solution?a)3 litersb)3.2 litersc)3.6 litersd)4 literse)4.2 litersCorrect answer is option 'D'. Can you explain this answer?
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Two solutions of acid were mixed to obtain 10 liters of new solution. Before they were mixed, the first solution contained 0.8 liters of acid while the second contained 0.6 liters of acid. If the percentage of acid in the first solution was twice that in the second, what was the volume of the first solution?a)3 litersb)3.2 litersc)3.6 litersd)4 literse)4.2 litersCorrect answer is option 'D'. Can you explain this answer? for GMAT 2024 is part of GMAT preparation. The Question and answers have been prepared according to the GMAT exam syllabus. Information about Two solutions of acid were mixed to obtain 10 liters of new solution. Before they were mixed, the first solution contained 0.8 liters of acid while the second contained 0.6 liters of acid. If the percentage of acid in the first solution was twice that in the second, what was the volume of the first solution?a)3 litersb)3.2 litersc)3.6 litersd)4 literse)4.2 litersCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for GMAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two solutions of acid were mixed to obtain 10 liters of new solution. Before they were mixed, the first solution contained 0.8 liters of acid while the second contained 0.6 liters of acid. If the percentage of acid in the first solution was twice that in the second, what was the volume of the first solution?a)3 litersb)3.2 litersc)3.6 litersd)4 literse)4.2 litersCorrect answer is option 'D'. Can you explain this answer?.
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