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From a pack of 52 cards, one black ace, one red king, one black queen and all the four jacks were lost. Find the probability that one card picked out of the remaining cards would be a queen.
  • a)
    1/4
  • b)
    1/13
  • c)
    1/15
  • d)
    3/13
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
From a pack of 52 cards, one black ace, one red king, one black queen ...
Formula used: 
Probability (E) = (Number of favorable outcomes)/(Total no. of possible outcomes)
Calculation:
Total number of cards = 52
After removing one black ace, one black queen and all the four jacks,
Number of remaining card = 52 - 7 = 45
Number of queen remaining = 3
Therefore, 3C1(Selecting one out of remaining 3)times out of  45C1( Selecting 1 out of 45 items) a queen is picked.
Now,
Probability (E) = 3C1/45C1 = ​​3/45 = 1/15
∴ The required probability is 1/15.
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Most Upvoted Answer
From a pack of 52 cards, one black ace, one red king, one black queen ...
Formula used: 
Probability (E) = (Number of favorable outcomes)/(Total no. of possible outcomes)
Calculation:
Total number of cards = 52
After removing one black ace, one black queen and all the four jacks,
Number of remaining card = 52 - 7 = 45
Number of queen remaining = 3
Therefore, 3C1(Selecting one out of remaining 3)times out of  45C1( Selecting 1 out of 45 items) a queen is picked.
Now,
Probability (E) = 3C1/45C1 = ​​3/45 = 1/15
∴ The required probability is 1/15.
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From a pack of 52 cards, one black ace, one red king, one black queen and all the four jacks were lost. Find the probability that one card picked out of the remaining cards would be a queen.a)1/4b)1/13c)1/15d)3/13Correct answer is option 'C'. Can you explain this answer?
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