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If 80% of my age 6 years ago is the same as 60% of my age after 10 years. What is the product of digits of my present age?
  • a)
    24
  • b)
    20
  • c)
    30
  • d)
    15
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
If 80% of my age 6 years ago is the same as 60% of my age after 10 yea...
Let the present age be x
⇒ Six years ago my age will be = (x - 6)
⇒ Age after 10 years = (x + 10)
According to the question
⇒ 80% of (x – 6) = 60% of (x + 10)
⇒ 4x – 24 = 3x + 30
⇒ x = 54
∴ Product of digits = 5 × 4 = 20
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Most Upvoted Answer
If 80% of my age 6 years ago is the same as 60% of my age after 10 yea...
Let's assume the present age as 'x'.

Given that 80% of the age 6 years ago is the same as 60% of the age after 10 years, we can write the equation as:

0.8(x - 6) = 0.6(x + 10)

Simplifying this equation:

0.8x - 4.8 = 0.6x + 6

Subtracting 0.6x from both sides:

0.2x - 4.8 = 6

Adding 4.8 to both sides:

0.2x = 10.8

Dividing both sides by 0.2:

x = 54

Therefore, the present age is 54.

To find the product of the digits of the present age, we can multiply the digits together:

Product = 5 * 4 = 20

Hence, the product of the digits of the present age is 20, which corresponds to option B.
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Community Answer
If 80% of my age 6 years ago is the same as 60% of my age after 10 yea...
Let the present age be x
⇒ Six years ago my age will be = (x - 6)
⇒ Age after 10 years = (x + 10)
According to the question
⇒ 80% of (x – 6) = 60% of (x + 10)
⇒ 4x – 24 = 3x + 30
⇒ x = 54
∴ Product of digits = 5 × 4 = 20
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If 80% of my age 6 years ago is the same as 60% of my age after 10 years. What is the product of digits of my present age?a)24b)20c)30d)15Correct answer is option 'B'. Can you explain this answer?
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