If 80% of my age 6 years ago is the same as 60% of my age after 10 yea...
Let the present age be x
⇒ Six years ago my age will be = (x - 6)
⇒ Age after 10 years = (x + 10)
According to the question
⇒ 80% of (x – 6) = 60% of (x + 10)
⇒ 4x – 24 = 3x + 30
⇒ x = 54
∴ Product of digits = 5 × 4 = 20
View all questions of this testIf 80% of my age 6 years ago is the same as 60% of my age after 10 yea...
Let's assume the present age as 'x'.
Given that 80% of the age 6 years ago is the same as 60% of the age after 10 years, we can write the equation as:
0.8(x - 6) = 0.6(x + 10)
Simplifying this equation:
0.8x - 4.8 = 0.6x + 6
Subtracting 0.6x from both sides:
0.2x - 4.8 = 6
Adding 4.8 to both sides:
0.2x = 10.8
Dividing both sides by 0.2:
x = 54
Therefore, the present age is 54.
To find the product of the digits of the present age, we can multiply the digits together:
Product = 5 * 4 = 20
Hence, the product of the digits of the present age is 20, which corresponds to option B.
If 80% of my age 6 years ago is the same as 60% of my age after 10 yea...
Let the present age be x
⇒ Six years ago my age will be = (x - 6)
⇒ Age after 10 years = (x + 10)
According to the question
⇒ 80% of (x – 6) = 60% of (x + 10)
⇒ 4x – 24 = 3x + 30
⇒ x = 54
∴ Product of digits = 5 × 4 = 20