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If the radius of a sphere is 1/(4π)m and the electric flux density is 16π units, the total flux is given by,
  • a)
    2
  • b)
    3
  • c)
    4
  • d)
    5
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
If the radius of a sphere is 1/(4π)m and the electric flux density ...
Given Data:
Radius of the sphere, r = 1/(4π) m
Electric flux density, D = 16π units

Calculating Total Flux:
The total electric flux Φ through a closed surface is given by the formula:
Φ = ∮ D · dA
Since the electric flux density D is constant and perpendicular to the surface of the sphere, the flux through the entire surface of the sphere can be calculated by:
Φ = D * A
Where A is the total surface area of the sphere, given by:
A = 4πr^2
Substitute the given values:
A = 4π(1/(4π))^2
A = 1
Therefore, the total electric flux Φ is:
Φ = D * A
Φ = 16π * 1
Φ = 16π

Answer:
Therefore, the total flux is 16π units, which corresponds to option 'C'.
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Community Answer
If the radius of a sphere is 1/(4π)m and the electric flux density ...
Total flux leaving the entire surface is, ψ = 4πr2D from Gauss law. Ψ = 4π(1/16π2) X 16π = 4.
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If the radius of a sphere is 1/(4π)m and the electric flux density is 16π units, the total flux is given by,a)2b)3c)4d)5Correct answer is option 'C'. Can you explain this answer?
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