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A three-phase balanced delta connected load of (4 + j8) Ω is connected across a 400V, 3 – Ø balanced supply. Determine the phase current IR. Assume the phase sequence to be RYB.
  • a)
    44.74 ∠ -63.4⁰A
  • b)
    44.74 ∠ 63.4⁰A
  • c)
    45.74 ∠ -63.4⁰A
  • d)
    45.74 ∠ 63.4⁰A
Correct answer is option 'A'. Can you explain this answer?
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Taking the line voltage VRY = V∠0⁰ as a reference VRY = 400∠0⁰V, VYB = 400 ∠ -120 ⁰V and VBR = 400∠-240⁰V. Impedance per phase = (4 + j8) Ω = 8.94∠63.4⁰Ω. Phase current IR = (400∠0o)/(8.94∠63.4o )= 44.74 ∠ -63.4⁰A.
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A three-phase balanced delta connected load of (4 + j8) is connected across a 400V, 3 – Ø balanced supply. Determine the phase current IR. Assume the phase sequence to be RYB.a)44.74 ∠ -63.4Ab)44.74 ∠ 63.4Ac)45.74 ∠ -63.4Ad)45.74 ∠ 63.4ACorrect answer is option 'A'. Can you explain this answer?
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