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An organic compound shows the following spectral da Mass IR : 130 (Molecular Weight) : 3082-2860, 1825, 1755, 1455c * m ^ - 1 'HNMR 1.30 (triplet, J = 7.1Hz ) and 2.20 (quartet, J = 7.1Hz ) and ratio of pe areas = 3.2. Extablish the structure of the compound?
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An organic compound shows the following spectral da Mass IR : 130 (Mol...
Solution:

To establish the structure of the given organic compound, we will analyze the spectral data provided, including the molecular weight, IR spectrum, and 'HNMR spectrum.

1. Molecular Weight:
The molecular weight of the compound is given as 130 g/mol.

2. IR Spectrum:
The IR spectrum provides information about the functional groups present in the compound. The following peaks are observed:

- 3082-2860 cm^-1: These peaks indicate the presence of C-H stretching vibrations in alkanes or alkyl groups.
- 1825 cm^-1: This peak suggests the presence of a carbonyl group (C=O) in the compound.
- 1755 cm^-1: This peak indicates the presence of another carbonyl group (C=O) in the compound.
- 1455 cm^-1: This peak suggests the presence of a C-H bending vibration in an alkane or alkyl group.

3. 'HNMR Spectrum:
The 'HNMR spectrum provides information about the hydrogen atoms in the compound. The following peaks are observed:

- 1.30 ppm (triplet, J = 7.1Hz): This peak corresponds to a hydrogen atom that is coupled to two other hydrogen atoms. The coupling constant (J) of 7.1 Hz suggests that the two neighboring hydrogen atoms are separated by three bonds.
- 2.20 ppm (quartet, J = 7.1Hz): This peak corresponds to a hydrogen atom that is coupled to three other hydrogen atoms. The coupling constant (J) of 7.1 Hz suggests that the three neighboring hydrogen atoms are separated by two bonds.

The ratio of peak areas (integration values) for these two peaks is given as 3.2.

Structure Determination:

Based on the spectral data provided, we can propose the following structure for the organic compound:

- The molecular weight of 130 g/mol suggests a relatively small compound.
- The presence of C-H stretching vibrations in the IR spectrum indicates the presence of alkyl groups.
- The presence of two carbonyl groups (C=O) in the IR spectrum suggests the presence of two carbonyl-containing functional groups in the compound.
- The 'HNMR spectrum indicates the presence of two different hydrogen environments, one with a coupling pattern of a triplet and the other with a quartet.

Taking all these observations into account, we can propose that the compound is a ketone with the following structure:

Structure:
```
O
||
C - C - C - C - C - C - C - C - C - C - C - C - C - C - C - C - C - C - C - C - C - C - C - C - C - C
| | | | | | | | | | | | | | | | | | | | | | | |
H - H - H - H - H - H - H - H - H - H - H - H - H - H - H - H - H - H - H - H - H - H - H - H - H - O - H
Triplet Quartet
```

In
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An organic compound shows the following spectral da Mass IR : 130 (Molecular Weight) : 3082-2860, 1825, 1755, 1455c * m ^ - 1 'HNMR 1.30 (triplet, J = 7.1Hz ) and 2.20 (quartet, J = 7.1Hz ) and ratio of pe areas = 3.2. Extablish the structure of the compound?
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An organic compound shows the following spectral da Mass IR : 130 (Molecular Weight) : 3082-2860, 1825, 1755, 1455c * m ^ - 1 'HNMR 1.30 (triplet, J = 7.1Hz ) and 2.20 (quartet, J = 7.1Hz ) and ratio of pe areas = 3.2. Extablish the structure of the compound? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about An organic compound shows the following spectral da Mass IR : 130 (Molecular Weight) : 3082-2860, 1825, 1755, 1455c * m ^ - 1 'HNMR 1.30 (triplet, J = 7.1Hz ) and 2.20 (quartet, J = 7.1Hz ) and ratio of pe areas = 3.2. Extablish the structure of the compound? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An organic compound shows the following spectral da Mass IR : 130 (Molecular Weight) : 3082-2860, 1825, 1755, 1455c * m ^ - 1 'HNMR 1.30 (triplet, J = 7.1Hz ) and 2.20 (quartet, J = 7.1Hz ) and ratio of pe areas = 3.2. Extablish the structure of the compound?.
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