The rate if the reaction ch3cooc2h5 naoh gives raise ch3coona c2h5o...
The Effect of Adding Water on the Rate of the Reaction
Introduction:
The given reaction is the saponification of an ester, where ethyl acetate (CH3COOC2H5) reacts with sodium hydroxide (NaOH) to form sodium acetate (CH3COONa) and ethanol (C2H5OH). The rate of this reaction is given by the equation rate = k(CH3COOC2H5)(NaOH), where k is the rate constant.
Explanation:
When water is added to the reaction mixture, it dilutes the solution and affects the concentrations of the reactants. This, in turn, affects the rate of the reaction.
Effect on Concentrations:
Adding water increases the total volume of the reaction mixture, but it does not change the number of moles of the reactants. Therefore, the concentrations of CH3COOC2H5 and NaOH decrease when water is added.
Rate Expression:
The rate expression of the reaction is given by rate = k(CH3COOC2H5)(NaOH). As the concentrations of CH3COOC2H5 and NaOH decrease due to the addition of water, the rate of the reaction also decreases.
Comparison of Rates:
To compare the rate of the reaction after adding water to the original rate, we can calculate the ratio of the two rates.
Let's assume the original rate of the reaction is R1 and the rate after adding water is R2.
The ratio of the rates can be calculated as:
Ratio = R2 / R1
Conclusion:
Adding water to the reaction mixture decreases the concentrations of CH3COOC2H5 and NaOH, resulting in a decrease in the rate of the reaction. The ratio of the rate after adding water to the original rate can be calculated to determine the exact change in the rate.