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The rate of the reaction ch3cooc2h5 naoh gives raise ch3coona c2h5oh is given as rate =k (ch3coona)naoh) if three times water is added to the reaction mixture the rate of the reaction compared to the original rate will be?
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The rate of the reaction ch3cooc2h5 naoh gives raise ch3coona c2h5oh...
Rate of the Reaction:
The rate of a chemical reaction is defined as the change in concentration of a reactant or product per unit time. In this case, the rate of the reaction CH3COOC2H5 + NaOH → CH3COONa + C2H5OH can be expressed as rate = k [CH3COONa][NaOH], where k is the rate constant.
Effect of Adding Water:
When water is added to the reaction mixture, it will increase the total volume of the solution. This will result in a decrease in the concentration of both CH3COONa and NaOH. However, the ratio of their concentrations ([CH3COONa]/[NaOH]) will remain constant, as it is determined by the stoichiometry of the balanced chemical equation.
Explanation:
When three times water is added to the reaction mixture, the concentration of both CH3COONa and NaOH will decrease by a factor of 3. Let's assume the original rate of the reaction is R1.
Comparison of Rates:
The rate equation for the reaction, rate = k [CH3COONa] [NaOH], shows that the rate is directly proportional to the concentrations of both CH3COONa and NaOH. Therefore, when the concentrations of these reactants decrease by a factor of 3, the rate of the reaction will also decrease by the same factor.
The rate of the reaction after adding three times water can be expressed as R2 = k ([CH3COONa]/3) ([NaOH]/3). Simplifying this expression, we get R2 = (1/9) k [CH3COONa] [NaOH].
Comparing the rates R1 and R2, we can see that R2 is (1/9) times R1. Therefore, the rate of the reaction after adding three times water is 1/9th of the original rate.
Summary:
When three times water is added to the reaction mixture, the rate of the reaction CH3COOC2H5 + NaOH → CH3COONa + C2H5OH will decrease by a factor of 9. This is because the concentrations of both CH3COONa and NaOH decrease by a factor of 3, leading to a decrease in the rate of the reaction.
The rate of a chemical reaction is defined as the change in concentration of a reactant or product per unit time. In this case, the rate of the reaction CH3COOC2H5 + NaOH → CH3COONa + C2H5OH can be expressed as rate = k [CH3COONa][NaOH], where k is the rate constant.
Effect of Adding Water:
When water is added to the reaction mixture, it will increase the total volume of the solution. This will result in a decrease in the concentration of both CH3COONa and NaOH. However, the ratio of their concentrations ([CH3COONa]/[NaOH]) will remain constant, as it is determined by the stoichiometry of the balanced chemical equation.
Explanation:
When three times water is added to the reaction mixture, the concentration of both CH3COONa and NaOH will decrease by a factor of 3. Let's assume the original rate of the reaction is R1.
Comparison of Rates:
The rate equation for the reaction, rate = k [CH3COONa] [NaOH], shows that the rate is directly proportional to the concentrations of both CH3COONa and NaOH. Therefore, when the concentrations of these reactants decrease by a factor of 3, the rate of the reaction will also decrease by the same factor.
The rate of the reaction after adding three times water can be expressed as R2 = k ([CH3COONa]/3) ([NaOH]/3). Simplifying this expression, we get R2 = (1/9) k [CH3COONa] [NaOH].
Comparing the rates R1 and R2, we can see that R2 is (1/9) times R1. Therefore, the rate of the reaction after adding three times water is 1/9th of the original rate.
Summary:
When three times water is added to the reaction mixture, the rate of the reaction CH3COOC2H5 + NaOH → CH3COONa + C2H5OH will decrease by a factor of 9. This is because the concentrations of both CH3COONa and NaOH decrease by a factor of 3, leading to a decrease in the rate of the reaction.
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The rate of the reaction ch3cooc2h5 naoh gives raise ch3coona c2h5oh is given as rate =k (ch3coona)naoh) if three times water is added to the reaction mixture the rate of the reaction compared to the original rate will be?
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The rate of the reaction ch3cooc2h5 naoh gives raise ch3coona c2h5oh is given as rate =k (ch3coona)naoh) if three times water is added to the reaction mixture the rate of the reaction compared to the original rate will be? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The rate of the reaction ch3cooc2h5 naoh gives raise ch3coona c2h5oh is given as rate =k (ch3coona)naoh) if three times water is added to the reaction mixture the rate of the reaction compared to the original rate will be? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The rate of the reaction ch3cooc2h5 naoh gives raise ch3coona c2h5oh is given as rate =k (ch3coona)naoh) if three times water is added to the reaction mixture the rate of the reaction compared to the original rate will be?.
The rate of the reaction ch3cooc2h5 naoh gives raise ch3coona c2h5oh is given as rate =k (ch3coona)naoh) if three times water is added to the reaction mixture the rate of the reaction compared to the original rate will be? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The rate of the reaction ch3cooc2h5 naoh gives raise ch3coona c2h5oh is given as rate =k (ch3coona)naoh) if three times water is added to the reaction mixture the rate of the reaction compared to the original rate will be? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The rate of the reaction ch3cooc2h5 naoh gives raise ch3coona c2h5oh is given as rate =k (ch3coona)naoh) if three times water is added to the reaction mixture the rate of the reaction compared to the original rate will be?.
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