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The general value of θ which satisfies the equations sinθ = -(1/2) and tanθ = (1/√3) is
- a)2nπ + (π/6
- b)nπ + (π/6)
- c)nπ - (π/6)
- d)2nπ + (7π/6)
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
The general value of θ which satisfies the equations sinθ ...
Hence in third quodrant sin-1/2 and tan1√3 are common so
angle (thitha)=210
in π term thitha=210×π/180=7π/6
thitha=2nπ+alpha
here alpha=7π/6
so thitha=2nπ+7π/6
angle (thitha)=210
in π term thitha=210×π/180=7π/6
thitha=2nπ+alpha
here alpha=7π/6
so thitha=2nπ+7π/6
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The general value of θ which satisfies the equations sinθ ...
Given Equations:
- sinθ = -(1/2)
- tanθ = (1/√3)
Solution:
Finding the value of θ using sinθ = -(1/2)
- In the second quadrant, sinθ is negative and equals -(1/2) at θ = 7π/6.
- The general solution for sinθ = -(1/2) is θ = 2nπ + (7π/6).
Finding the value of θ using tanθ = (1/√3)
- In the first quadrant, tanθ is positive and equals (1/√3) at θ = π/6.
- The general solution for tanθ = (1/√3) is θ = nπ + (π/6).
Combining both solutions:
- Since both sinθ and tanθ must be satisfied simultaneously, we need to find a common value of θ that satisfies both conditions.
- The common value that satisfies both equations is θ = 2nπ + (7π/6).
Therefore, the general value of θ which satisfies the given equations is 2nπ + (7π/6), which corresponds to option 'D'.
- sinθ = -(1/2)
- tanθ = (1/√3)
Solution:
Finding the value of θ using sinθ = -(1/2)
- In the second quadrant, sinθ is negative and equals -(1/2) at θ = 7π/6.
- The general solution for sinθ = -(1/2) is θ = 2nπ + (7π/6).
Finding the value of θ using tanθ = (1/√3)
- In the first quadrant, tanθ is positive and equals (1/√3) at θ = π/6.
- The general solution for tanθ = (1/√3) is θ = nπ + (π/6).
Combining both solutions:
- Since both sinθ and tanθ must be satisfied simultaneously, we need to find a common value of θ that satisfies both conditions.
- The common value that satisfies both equations is θ = 2nπ + (7π/6).
Therefore, the general value of θ which satisfies the given equations is 2nπ + (7π/6), which corresponds to option 'D'.
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The general value of θ which satisfies the equations sinθ = -(1/2) and tanθ = (1/√3) isa)2nπ + (π/6b)nπ + (π/6)c)nπ - (π/6)d)2nπ + (7π/6)Correct answer is option 'D'. Can you explain this answer?
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The general value of θ which satisfies the equations sinθ = -(1/2) and tanθ = (1/√3) isa)2nπ + (π/6b)nπ + (π/6)c)nπ - (π/6)d)2nπ + (7π/6)Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The general value of θ which satisfies the equations sinθ = -(1/2) and tanθ = (1/√3) isa)2nπ + (π/6b)nπ + (π/6)c)nπ - (π/6)d)2nπ + (7π/6)Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The general value of θ which satisfies the equations sinθ = -(1/2) and tanθ = (1/√3) isa)2nπ + (π/6b)nπ + (π/6)c)nπ - (π/6)d)2nπ + (7π/6)Correct answer is option 'D'. Can you explain this answer?.
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