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If tanθ=-(1/√3), sinθ=(1/2), cosθ=-(√3/2), the principal value of θ is
  • a)
    π/6
  • b)
    (5π/6)
  • c)
    (7π/6)
  • d)
    -(π/6)
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
If tanθ=-(1/√3), sinθ=(1/2), cosθ=-(√3/2...
Since we don't have a specific value for tan, we cannot solve this problem.
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If tanθ=-(1/√3), sinθ=(1/2), cosθ=-(√3/2), the principal value of θ isa)π/6b)(5π/6)c)(7π/6)d)-(π/6)Correct answer is option 'B'. Can you explain this answer?
Question Description
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