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What will be the output of the following code snippet?
#include <stdio.h>
void solve() {
    int ch = 2;
    switch(ch) {
        case 1: printf("1 ");
        case 2: printf("2 ");
        case 3: printf("3 ");
        default: printf("None");
    }
}
int main() {
    solve();
    return 0;
}
  • a)
    1 2 3 None
  • b)
    2
  • c)
    2 3 None
  • d)
    None
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
What will be the output of the following code snippet?#include <std...
In the given code snippet, the variable 'ch' is initialized with the value '2'. The code uses a switch statement to determine the output based on the value of 'ch'.
The switch statement starts by evaluating the value of 'ch'. It then compares the value of 'ch' with the constant values in the case labels. When it finds a match, it starts executing the code from that case label until it reaches a 'break' statement or the end of the switch block.
Let's go through the switch cases:
  • 'case 1': The value of 'ch' is '2', so this case is skipped.
  • 'case 2': The value of 'ch' matches the constant '2', so the code under this case is executed. It prints "2 ".
  • 'case 3': There is no 'break' statement after the 'case 2', so the control falls through to this case. The value of ch is 2, not 3, so this case is also executed. It prints "3 ".
  • 'default': Since there is no 'break' statement after the 'case 3', the control falls through to the 'default' case. The 'default' case doesn't have any specific condition, so it acts as a catch-all case. It prints "None".
Therefore, the output of the code snippet will be "2 3 None".
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Most Upvoted Answer
What will be the output of the following code snippet?#include <std...
In the given code snippet, the variable 'ch' is initialized with the value '2'. The code uses a switch statement to determine the output based on the value of 'ch'.
The switch statement starts by evaluating the value of 'ch'. It then compares the value of 'ch' with the constant values in the case labels. When it finds a match, it starts executing the code from that case label until it reaches a 'break' statement or the end of the switch block.
Let's go through the switch cases:
  • 'case 1': The value of 'ch' is '2', so this case is skipped.
  • 'case 2': The value of 'ch' matches the constant '2', so the code under this case is executed. It prints "2 ".
  • 'case 3': There is no 'break' statement after the 'case 2', so the control falls through to this case. The value of ch is 2, not 3, so this case is also executed. It prints "3 ".
  • 'default': Since there is no 'break' statement after the 'case 3', the control falls through to the 'default' case. The 'default' case doesn't have any specific condition, so it acts as a catch-all case. It prints "None".
Therefore, the output of the code snippet will be "2 3 None".
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Community Answer
What will be the output of the following code snippet?#include <std...

Explanation:

- The code snippet defines a function solve() that initializes a variable ch to 2 and then uses a switch statement to print different messages based on the value of ch.
- In the switch statement, the case 1 label is skipped because ch is 2. Hence, the program directly enters the case 2 block and prints "2 ".
- Since there are no break statements after each case, the control flows through all subsequent cases. Therefore, after printing "2 ", it also prints "3 ".
- Finally, there is a default case that prints "None".
- Therefore, the output of the code snippet is "2 3 None".
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What will be the output of the following code snippet?#include <stdio.h>void solve() { int ch = 2; switch(ch) { case 1: printf("1 "); case 2: printf("2 "); case 3: printf("3 "); default: printf("None"); }}int main() { solve(); return 0;}a)1 2 3 Noneb)2c)2 3 Noned)NoneCorrect answer is option 'C'. Can you explain this answer?
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