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Guys I wanna know what book is this question is from (electromagnetics)
When an electric oscillator is connected an antenna a uniform plane wave is produced in free space, the wavelength is found to be 40cm. when the same signal is produced in a certain non magnetic material, the wavelength is found to be 25 cm. calculate: The frequency of the oscillator (f). b) The relative permittivity the dielectric material?
When an electric oscillator is connected an antenna a uniform plane wave is produced in free space, the wavelength is found to be 40cm. when the same signal is produced in a certain non magnetic material, the wavelength is found to be 25 cm. calculate: The frequency of the oscillator (f). b) The relative permittivity the dielectric material?
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Guys I wanna know what book is this question is from (electromagnetics...
Book: Electromagnetics
Question:
When an electric oscillator is connected to an antenna, a uniform plane wave is produced in free space. The wavelength is found to be 40cm. When the same signal is produced in a certain non-magnetic material, the wavelength is found to be 25 cm. Calculate:
a) The frequency of the oscillator (f).
b) The relative permittivity of the dielectric material.
Solution:
a) Calculation of Frequency (f):
The speed of light in free space, c, is given by the formula:
c = λf
Where:
c = speed of light = 3 x 10^8 meters per second (m/s)
λ = wavelength
f = frequency
In the given problem, the wavelength in free space is 40 cm. Converting it to meters:
λ = 40 cm = 0.4 m
Using the formula, we can rearrange it to solve for frequency:
f = c / λ
f = (3 x 10^8 m/s) / (0.4 m)
f = 7.5 x 10^8 Hz
Therefore, the frequency of the oscillator is 7.5 x 10^8 Hz.
b) Calculation of Relative Permittivity (εr):
The relationship between the wavelength in a material and the wavelength in free space is given by:
λ = λ0 / √εr
Where:
λ = wavelength in the material
λ0 = wavelength in free space
εr = relative permittivity of the material
In the given problem, the wavelength in the material is 25 cm. Converting it to meters:
λ = 25 cm = 0.25 m
We can rearrange the formula to solve for the relative permittivity:
εr = (λ0 / λ)^2
εr = (0.4 m / 0.25 m)^2
εr = 2.56
Therefore, the relative permittivity of the dielectric material is 2.56.
Explanation:
- When an electric oscillator is connected to an antenna, it produces a uniform plane wave in free space.
- The wavelength in free space, denoted as λ0, is the distance between two consecutive peaks or troughs of the wave.
- The frequency of the oscillator, denoted as f, represents the number of complete oscillations the oscillator makes per second.
- The relationship between the wavelength and frequency is given by the formula c = λf, where c is the speed of light in free space.
- By rearranging the formula, we can solve for the frequency f = c / λ.
- In the given problem, the wavelength in free space is 40 cm, which is converted to meters as 0.4 m. Substituting the values, we find the frequency to be 7.5 x 10^8 Hz.
- When the same signal is produced in a certain non-magnetic material, the wavelength changes due to the interaction between the wave and the material
Question:
When an electric oscillator is connected to an antenna, a uniform plane wave is produced in free space. The wavelength is found to be 40cm. When the same signal is produced in a certain non-magnetic material, the wavelength is found to be 25 cm. Calculate:
a) The frequency of the oscillator (f).
b) The relative permittivity of the dielectric material.
Solution:
a) Calculation of Frequency (f):
The speed of light in free space, c, is given by the formula:
c = λf
Where:
c = speed of light = 3 x 10^8 meters per second (m/s)
λ = wavelength
f = frequency
In the given problem, the wavelength in free space is 40 cm. Converting it to meters:
λ = 40 cm = 0.4 m
Using the formula, we can rearrange it to solve for frequency:
f = c / λ
f = (3 x 10^8 m/s) / (0.4 m)
f = 7.5 x 10^8 Hz
Therefore, the frequency of the oscillator is 7.5 x 10^8 Hz.
b) Calculation of Relative Permittivity (εr):
The relationship between the wavelength in a material and the wavelength in free space is given by:
λ = λ0 / √εr
Where:
λ = wavelength in the material
λ0 = wavelength in free space
εr = relative permittivity of the material
In the given problem, the wavelength in the material is 25 cm. Converting it to meters:
λ = 25 cm = 0.25 m
We can rearrange the formula to solve for the relative permittivity:
εr = (λ0 / λ)^2
εr = (0.4 m / 0.25 m)^2
εr = 2.56
Therefore, the relative permittivity of the dielectric material is 2.56.
Explanation:
- When an electric oscillator is connected to an antenna, it produces a uniform plane wave in free space.
- The wavelength in free space, denoted as λ0, is the distance between two consecutive peaks or troughs of the wave.
- The frequency of the oscillator, denoted as f, represents the number of complete oscillations the oscillator makes per second.
- The relationship between the wavelength and frequency is given by the formula c = λf, where c is the speed of light in free space.
- By rearranging the formula, we can solve for the frequency f = c / λ.
- In the given problem, the wavelength in free space is 40 cm, which is converted to meters as 0.4 m. Substituting the values, we find the frequency to be 7.5 x 10^8 Hz.
- When the same signal is produced in a certain non-magnetic material, the wavelength changes due to the interaction between the wave and the material
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Guys I wanna know what book is this question is from (electromagnetics)When an electric oscillator is connected an antenna a uniform plane wave is produced in free space, the wavelength is found to be 40cm. when the same signal is produced in a certain non magnetic material, the wavelength is found to be 25 cm. calculate: The frequency of the oscillator (f). b) The relative permittivity the dielectric material?
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Guys I wanna know what book is this question is from (electromagnetics)When an electric oscillator is connected an antenna a uniform plane wave is produced in free space, the wavelength is found to be 40cm. when the same signal is produced in a certain non magnetic material, the wavelength is found to be 25 cm. calculate: The frequency of the oscillator (f). b) The relative permittivity the dielectric material? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about Guys I wanna know what book is this question is from (electromagnetics)When an electric oscillator is connected an antenna a uniform plane wave is produced in free space, the wavelength is found to be 40cm. when the same signal is produced in a certain non magnetic material, the wavelength is found to be 25 cm. calculate: The frequency of the oscillator (f). b) The relative permittivity the dielectric material? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Guys I wanna know what book is this question is from (electromagnetics)When an electric oscillator is connected an antenna a uniform plane wave is produced in free space, the wavelength is found to be 40cm. when the same signal is produced in a certain non magnetic material, the wavelength is found to be 25 cm. calculate: The frequency of the oscillator (f). b) The relative permittivity the dielectric material?.
Guys I wanna know what book is this question is from (electromagnetics)When an electric oscillator is connected an antenna a uniform plane wave is produced in free space, the wavelength is found to be 40cm. when the same signal is produced in a certain non magnetic material, the wavelength is found to be 25 cm. calculate: The frequency of the oscillator (f). b) The relative permittivity the dielectric material? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about Guys I wanna know what book is this question is from (electromagnetics)When an electric oscillator is connected an antenna a uniform plane wave is produced in free space, the wavelength is found to be 40cm. when the same signal is produced in a certain non magnetic material, the wavelength is found to be 25 cm. calculate: The frequency of the oscillator (f). b) The relative permittivity the dielectric material? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Guys I wanna know what book is this question is from (electromagnetics)When an electric oscillator is connected an antenna a uniform plane wave is produced in free space, the wavelength is found to be 40cm. when the same signal is produced in a certain non magnetic material, the wavelength is found to be 25 cm. calculate: The frequency of the oscillator (f). b) The relative permittivity the dielectric material?.
Solutions for Guys I wanna know what book is this question is from (electromagnetics)When an electric oscillator is connected an antenna a uniform plane wave is produced in free space, the wavelength is found to be 40cm. when the same signal is produced in a certain non magnetic material, the wavelength is found to be 25 cm. calculate: The frequency of the oscillator (f). b) The relative permittivity the dielectric material? in English & in Hindi are available as part of our courses for Electrical Engineering (EE).
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