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The average gate power dissipation for an SCR is 0.5 Watts the voltage applied to the gate is Vg = 10 V. What is the maximum value of current Ig for safe operation?
  • a)
    0.25 A
  • b)
    10 A
  • c)
    0.05 A
  • d)
    0.1 A
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The average gate power dissipation for an SCR is 0.5 Watts the voltage...
Given:
- Average gate power dissipation for an SCR is 0.5 Watts.
- Voltage applied to the gate is Vg = 10 V.

To find:
- Maximum value of current Ig for safe operation.

Formula:
The average power dissipated by the gate of an SCR can be calculated using the formula:

Pavg = Vg * Ig

where Pavg is the average power dissipation, Vg is the voltage applied to the gate, and Ig is the gate current.

Solution:
We are given that the average gate power dissipation is 0.5 Watts and the voltage applied to the gate is 10 V.

Substituting these values into the formula, we get:

0.5 = 10 * Ig

Rearranging the equation to solve for Ig, we have:

Ig = 0.5 / 10

Ig = 0.05 A

Therefore, the maximum value of current Ig for safe operation is 0.05 A.

Hence, the correct answer is option C) 0.05 A.
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Community Answer
The average gate power dissipation for an SCR is 0.5 Watts the voltage...
To determine the maximum value of current (Ig) for safe operation of an SCR (Silicon-Controlled Rectifier) when the average gate power dissipation and gate voltage are given, we can use the formula:
Pavg = Ig x Vg
Given that Pavg = 0.5 Watts and Vg = 10 V, we can rearrange the formula to solve for Ig:
Ig = Pavg / Vg
Substituting the given values:
Ig = 0.5 Watts / 10 V
Calculating the result:
Ig = 0.05 A
Therefore, the maximum value of current (Ig) for safe operation is 0.05 A, which corresponds to option C.
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The average gate power dissipation for an SCR is 0.5 Watts the voltage applied to the gate is Vg = 10 V. What is the maximum value of current Ig for safe operation?a)0.25 Ab)10 Ac)0.05 Ad)0.1 ACorrect answer is option 'C'. Can you explain this answer?
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