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Find the amplitude of the gate current pulse, when the gate-cathode curve is given by the relation Vg = [(1+10) x Ig] The peak gate drive power is 5 Watts.
  • a)
    359mA
  • b)
    659mA
  • c)
    1.359 A
  • d)
    1.659 A
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Find the amplitude of the gate current pulse, when the gate-cathode cu...
To find the amplitude of the gate current pulse, we need to analyze the given gate-cathode curve and the peak gate drive power.

The gate-cathode curve is given by the relation Vg = [(1 + 10) x Ig], where Vg is the gate voltage and Ig is the gate current. This equation represents a linear relationship between the gate voltage and gate current.

The peak gate drive power is given as 5 Watts. Power is defined as the product of voltage and current, so we can write the equation as P = Vg x Ig. We can rearrange this equation to solve for Ig: Ig = P / Vg.

Let's substitute the given values into the equation to find the gate current amplitude.

Given:
Peak gate drive power (P) = 5 Watts
Gate voltage (Vg) = (1 + 10) x Ig

Substituting these values into the equation, we get:
Ig = P / Vg
Ig = 5 / [(1 + 10) x Ig]

Simplifying the equation:
Ig = 5 / (11 x Ig)
11 x Ig x Ig = 5
Ig^2 = 5 / 11
Ig = sqrt(5 / 11) (taking the square root of both sides)
Ig = 0.659 A (approximately)

Therefore, the amplitude of the gate current pulse is 0.659 A, which corresponds to option B.
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Community Answer
Find the amplitude of the gate current pulse, when the gate-cathode cu...
(1+10 Ig).Ig = 5 Watts
Ig = 0.59 A.
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