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A bullet of mass 20 g is horizontally fixed with a velocity of 150m/s from pistol of mass 2kg . what is the xecoil velocity of the pistol ?
Verified Answer
A bullet of mass 20 g is horizontally fixed with a velocity of 150m/s ...
For bullet:

m1 = 20 g = 0.02kg

u1 = 0 m/s

v1 = 150 ms-1

For pistol:

m1 = 2kg

u1 = 0 m/s

v2 = ?

According to the law of conservation of momentum,

Total momenta after the fire = Total momenta before the fire.

That is, 

m1v1 + m2v2 = m1u1 + m2u2

0.20 x 150 + 2 x v2 = 0.02 x 0 + 2 x 0

rightwards double arrow       2v2 = -3

rightwards double arrow         v2 = -1.5 ms-1. 

Negative sign indicates that the direction in which the pistol would recoil is opposite to that of bullet.
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A bullet of mass 20 g is horizontally fixed with a velocity of 150m/s from pistol of mass 2kg . what is the xecoil velocity of the pistol ?
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