Let
2x+y+6=0...as equation 1
3x-2y-12=0...as equation 2
multiplying 2 in equation 1 then we get,
4x+2y+12=0...as. equation 3
multiplying 1 in equation 2 then we get,
3x-2y-12=0..as equation 4
simplified equation 3 and 4 then we get,
x=0
lastly we put the value of x in equation 1 then we get the value of y ...and the value of y is -6
X=0
y=-6

When we have two or more linear equations with two variables, we can find their solutions by graphing them on the coordinate plane. The point where the lines intersect is the solution to the system of equations.


Solve the following system of linear equations graphically:

2x + y = 6

3x - 2y - 12 = 0




To graph the equations, we need to rewrite them in slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept.

2x + y = 6

y = -2x + 6

3x - 2y - 12 = 0

-2y = -3x + 12

y = (3/2)x - 6


Now we can graph the lines on the coordinate plane by plotting their y-intercepts and using their slopes to find other points on the line.

The first equation has a y-intercept of 6 and a slope of -2. We can plot the point (0, 6) and use the slope to find another point, such as (3, 0).

The second equation has a y-intercept of -6 and a slope of 3/2. We can plot the point (0, -6) and use the slope to find another point, such as (4, 0).




The point where the lines intersect is the solution to the system of equations. In this case, it is (2, 2).



Therefore, the solution to the system of equations is x = 2 and y = 2.