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A shunt regulator utilizing a zener diode with an incremental resistance of 5 Ω is fed through an 82-Ω resistor. If the raw supply changes by 1.0 V, what is the corresponding change in the regulated output voltage?
  • a)
    72.7 mV
  • b)
    73.7 mV
  • c)
    74.7 mV
  • d)
    75.7 mV
Correct answer is option 'C'. Can you explain this answer?
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A shunt regulator is a type of voltage regulator that uses a shunt element, such as a zener diode, to regulate the output voltage. The zener diode is reverse biased and operates in the breakdown region, where it maintains a constant voltage across its terminals.

The incremental resistance of a zener diode is the change in voltage divided by the change in current, or ΔV/ΔI. In this case, the incremental resistance is given as 5.

To design a shunt regulator using a zener diode with an incremental resistance of 5, we need to determine the appropriate resistor value and current for the zener diode to operate within its specified range.

First, we need to calculate the minimum current required for the zener diode to maintain its breakdown voltage. The manufacturer's datasheet for the zener diode will provide the minimum zener current, commonly denoted as IZ(min). Let's assume IZ(min) = 5mA.

Next, we use Ohm's Law to calculate the resistor value required. The voltage across the resistor (VR) can be calculated as the difference between the input voltage (Vin) and the zener voltage (Vz). The current flowing through the resistor (IR) is the same as the zener current (IZ).

VR = Vin - Vz
IR = IZ

We can rearrange Ohm's Law to solve for the resistor value (R):

R = VR / IR

Let's assume Vin = 10V and Vz = 5V:

VR = 10V - 5V = 5V
IR = IZ(min) = 5mA = 0.005A

R = 5V / 0.005A = 1000Ω = 1kΩ

Therefore, a 1kΩ resistor should be used in conjunction with the zener diode to create a shunt regulator with an incremental resistance of 5. This combination will regulate the output voltage at the zener voltage (Vz) while maintaining a minimum zener current (IZ(min)) of 5mA.
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A shunt regulator utilizing a zener diode with an incremental resistance of 5 Ω is fed through an 82-Ω resistor. If the raw supply changes by 1.0 V, what is the corresponding change in the regulated output voltage?a)72.7 mVb)73.7 mVc)74.7 mVd)75.7 mVCorrect answer is option 'C'. Can you explain this answer?
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A shunt regulator utilizing a zener diode with an incremental resistance of 5 Ω is fed through an 82-Ω resistor. If the raw supply changes by 1.0 V, what is the corresponding change in the regulated output voltage?a)72.7 mVb)73.7 mVc)74.7 mVd)75.7 mVCorrect answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A shunt regulator utilizing a zener diode with an incremental resistance of 5 Ω is fed through an 82-Ω resistor. If the raw supply changes by 1.0 V, what is the corresponding change in the regulated output voltage?a)72.7 mVb)73.7 mVc)74.7 mVd)75.7 mVCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A shunt regulator utilizing a zener diode with an incremental resistance of 5 Ω is fed through an 82-Ω resistor. If the raw supply changes by 1.0 V, what is the corresponding change in the regulated output voltage?a)72.7 mVb)73.7 mVc)74.7 mVd)75.7 mVCorrect answer is option 'C'. Can you explain this answer?.
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