How is the 3rd element in an array accessed based on pointer notation?a)*a + 3b)*(a + 3)c)*(*a + 3)d)andamp;(a + 3)Correct answer is option 'B'. Can you explain this answer? - EduRev Electrical Engineering (EE) Question

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How is the 3rd element in an array accessed based on pointer notation?

a)
*a + 3
b)
*(a + 3)
c)
*(*a + 3)
d)
&(a + 3)

Correct answer is option 'B'. Can you explain this answer?

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Most Upvoted Answer

How is the 3rd element in an array accessed based on pointer notation?...

To access the 3rd element in an array using pointer notation, you can use the addition operator + to move the pointer to the desired element.

Here's the explanation:

Option 1. *a + 3: This expression would dereference the pointer a and add 3 to its value. However, it does not properly access the 3rd element in the array.
Option 2. *(a + 3): This expression correctly adds 3 to the pointer a, advancing it to the 3rd element in the array, and then dereferences the resulting pointer. This notation properly accesses the 3rd element in the array.
Option 3. *(*a + 3): This expression would attempt to dereference the pointer a, add 3 to its value, and then dereference the resulting value. It does not correctly access the 3rd element in the array.
Option 4. &(a + 3): This expression would attempt to take the address of the pointer a after adding 3 to its value. It does not correctly access the 3rd element in the array.

Therefore, the correct answer is: *(a + 3)

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How is the 3rd element in an array accessed based on pointer notation?...

C)*(*a+2)

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