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A student was interested in determining the relationship between the current, voltage, and resistance in a direct circuit, such as those exemplified by batteries connected to light bulbs. The student built the circuit presented in Figure 1 using a 2 ohm resistor.

The current that flows through the circuit can be calculated using the equation V=IR, where V is the voltage of the battery, I is the current flowing through the circuit, and R is the resistance of the resistor.
The student used a 2 ohm resistor and batteries of various voltages to obtain the results in Table 1. The currents shown in the table are NOT calculated using the formula V=IR, but instead directly measured from the circuit using an ammeter. It is important to note that the measured current will only exactly equal the calculated current if the system contains no internal resistance.
Q. In Experiment 1, how much current is most likely flowing through the circuit?
  • a)
    10 amps
  • b)
    1 amps
  • c)
    12 amps
  • d)
    5 amps
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A student was interested in determining the relationship between the c...
The passage provides us with a formula to calculate the amount of current running through the circuit, V=IR. We are told the voltage in Experiment 1 is 10 V and the resistor is 2 ohms, so 
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A student was interested in determining the relationship between the c...
The passage provides us with a formula to calculate the amount of current running through the circuit, V=IR. We are told the voltage in Experiment 1 is 10 V and the resistor is 2 ohms, so 
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Directions:Read the passages and choose the best answer to each question.PassageA group of students conducted several experiments using a variety of nonstick cookware, a spring scale, and several different weighted objects. Their goal was to determine which brand of cookware products had the best nonstick surface by measuring the coefficient of static friction, which is a measure of how resistant a stationary object is to movement.Experiment 1A student connected the spring scale to a weighted object that was placed inside a piece of nonstick cookware as shown in Figure 1.The students planned to calculate the coefficient of static friction by determining the force required to disturb an object from rest. During the experiment, one student anchored the nonstick cookware be holding tightly to the handle while the other student attached a weighted, smooth steel object to the spring scale. The student pulled on the spring until the object began to move. A third student recorded the force in newtons, N, indicated on the spring scale at the moment the object began to move across the nonstick surface.This procedure was repeated for 3 different brands of cookware; each brand of cookware was tested with various weighted objects. The coefficient of static friction was calculated by dividing the average force required to move the object by its weight (mass × g, the gravitational constant).The results are shown in Table 1.Experiment 2The students performed an experiment similar to Experiment 1, except three different brands of cooking spray were applied to the same cookware surface before the weights were put in place. The results are shown in Table 2.Q.The students’ instructor gave them one piece of nonstick cookware and asked them to identify the brand. The students repeated the procedures followed in Experiment 1 and obtained average forces of 0.088 N for the 150 gram object and 0.149 N for the 250 gram object. Which of the following brands would most likely have produced these results?

Directions:Read the passages and choose the best answer to each question.PassageA group of students conducted several experiments using a variety of nonstick cookware, a spring scale, and several different weighted objects. Their goal was to determine which brand of cookware products had the best nonstick surface by measuring the coefficient of static friction, which is a measure of how resistant a stationary object is to movement.Experiment 1A student connected the spring scale to a weighted object that was placed inside a piece of nonstick cookware as shown in Figure 1.The students planned to calculate the coefficient of static friction by determining the force required to disturb an object from rest. During the experiment, one student anchored the nonstick cookware be holding tightly to the handle while the other student attached a weighted, smooth steel object to the spring scale. The student pulled on the spring until the object began to move. A third student recorded the force in newtons, N, indicated on the spring scale at the moment the object began to move across the nonstick surface.This procedure was repeated for 3 different brands of cookware; each brand of cookware was tested with various weighted objects. The coefficient of static friction was calculated by dividing the average force required to move the object by its weight (mass × g, the gravitational constant).The results are shown in Table 1.Experiment 2The students performed an experiment similar to Experiment 1, except three different brands of cooking spray were applied to the same cookware surface before the weights were put in place. The results are shown in Table 2.Q.The results of the 2 experiments support the conclusion that as the weight of an object increases, the average force required to move it from rest generally

Directions:Read the passages and choose the best answer to each question.PassageA group of students conducted several experiments using a variety of nonstick cookware, a spring scale, and several different weighted objects. Their goal was to determine which brand of cookware products had the best nonstick surface by measuring the coefficient of static friction, which is a measure of how resistant a stationary object is to movement.Experiment 1A student connected the spring scale to a weighted object that was placed inside a piece of nonstick cookware as shown in Figure 1.The students planned to calculate the coefficient of static friction by determining the force required to disturb an object from rest. During the experiment, one student anchored the nonstick cookware be holding tightly to the handle while the other student attached a weighted, smooth steel object to the spring scale. The student pulled on the spring until the object began to move. A third student recorded the force in newtons, N, indicated on the spring scale at the moment the object began to move across the nonstick surface.This procedure was repeated for 3 different brands of cookware; each brand of cookware was tested with various weighted objects. The coefficient of static friction was calculated by dividing the average force required to move the object by its weight (mass × g, the gravitational constant).The results are shown in Table 1.Experiment 2The students performed an experiment similar to Experiment 1, except three different brands of cooking spray were applied to the same cookware surface before the weights were put in place. The results are shown in Table 2.Q.If Experiment 1 was repeated for Brand B cookware with a 200 gram mass, the average force needed to disturb the object from rest would be closest to

Directions:Read the passages and choose the best answer to each question.PassageA group of students conducted several experiments using a variety of nonstick cookware, a spring scale, and several different weighted objects. Their goal was to determine which brand of cookware products had the best nonstick surface by measuring the coefficient of static friction, which is a measure of how resistant a stationary object is to movement.Experiment 1A student connected the spring scale to a weighted object that was placed inside a piece of nonstick cookware as shown in Figure 1.The students planned to calculate the coefficient of static friction by determining the force required to disturb an object from rest. During the experiment, one student anchored the nonstick cookware be holding tightly to the handle while the other student attached a weighted, smooth steel object to the spring scale. The student pulled on the spring until the object began to move. A third student recorded the force in newtons, N, indicated on the spring scale at the moment the object began to move across the nonstick surface.This procedure was repeated for 3 different brands of cookware; each brand of cookware was tested with various weighted objects. The coefficient of static friction was calculated by dividing the average force required to move the object by its weight (mass × g, the gravitational constant).The results are shown in Table 1.Experiment 2The students performed an experiment similar to Experiment 1, except three different brands of cooking spray were applied to the same cookware surface before the weights were put in place. The results are shown in Table 2.Q.Which brand(s) of cooking spray was/were tested with only 2 different weights in Experiment 2?

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A student was interested in determining the relationship between the current, voltage, and resistance in a direct circuit, such as those exemplified by batteries connected to light bulbs. The student built the circuit presented in Figure 1 using a 2 ohm resistor.The current that flows through the circuit can be calculated using the equation V=IR, where V is the voltage of the battery, I is the current flowing through the circuit, and R is the resistance of the resistor.The student used a 2 ohm resistor and batteries of various voltages to obtain the results in Table 1. The currents shown in the table are NOT calculated using the formula V=IR, but instead directly measured from the circuit using an ammeter. It is important to note that the measured current will only exactly equal the calculated current if the system contains no internal resistance.Q.In Experiment 1, how much current is most likely flowing through the circuit?a)10 ampsb)1 ampsc)12 ampsd)5 ampsCorrect answer is option 'D'. Can you explain this answer?
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A student was interested in determining the relationship between the current, voltage, and resistance in a direct circuit, such as those exemplified by batteries connected to light bulbs. The student built the circuit presented in Figure 1 using a 2 ohm resistor.The current that flows through the circuit can be calculated using the equation V=IR, where V is the voltage of the battery, I is the current flowing through the circuit, and R is the resistance of the resistor.The student used a 2 ohm resistor and batteries of various voltages to obtain the results in Table 1. The currents shown in the table are NOT calculated using the formula V=IR, but instead directly measured from the circuit using an ammeter. It is important to note that the measured current will only exactly equal the calculated current if the system contains no internal resistance.Q.In Experiment 1, how much current is most likely flowing through the circuit?a)10 ampsb)1 ampsc)12 ampsd)5 ampsCorrect answer is option 'D'. Can you explain this answer? for ACT 2025 is part of ACT preparation. The Question and answers have been prepared according to the ACT exam syllabus. Information about A student was interested in determining the relationship between the current, voltage, and resistance in a direct circuit, such as those exemplified by batteries connected to light bulbs. The student built the circuit presented in Figure 1 using a 2 ohm resistor.The current that flows through the circuit can be calculated using the equation V=IR, where V is the voltage of the battery, I is the current flowing through the circuit, and R is the resistance of the resistor.The student used a 2 ohm resistor and batteries of various voltages to obtain the results in Table 1. The currents shown in the table are NOT calculated using the formula V=IR, but instead directly measured from the circuit using an ammeter. It is important to note that the measured current will only exactly equal the calculated current if the system contains no internal resistance.Q.In Experiment 1, how much current is most likely flowing through the circuit?a)10 ampsb)1 ampsc)12 ampsd)5 ampsCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for ACT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A student was interested in determining the relationship between the current, voltage, and resistance in a direct circuit, such as those exemplified by batteries connected to light bulbs. The student built the circuit presented in Figure 1 using a 2 ohm resistor.The current that flows through the circuit can be calculated using the equation V=IR, where V is the voltage of the battery, I is the current flowing through the circuit, and R is the resistance of the resistor.The student used a 2 ohm resistor and batteries of various voltages to obtain the results in Table 1. The currents shown in the table are NOT calculated using the formula V=IR, but instead directly measured from the circuit using an ammeter. It is important to note that the measured current will only exactly equal the calculated current if the system contains no internal resistance.Q.In Experiment 1, how much current is most likely flowing through the circuit?a)10 ampsb)1 ampsc)12 ampsd)5 ampsCorrect answer is option 'D'. Can you explain this answer?.
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It is important to note that the measured current will only exactly equal the calculated current if the system contains no internal resistance.Q.In Experiment 1, how much current is most likely flowing through the circuit?a)10 ampsb)1 ampsc)12 ampsd)5 ampsCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A student was interested in determining the relationship between the current, voltage, and resistance in a direct circuit, such as those exemplified by batteries connected to light bulbs. The student built the circuit presented in Figure 1 using a 2 ohm resistor.The current that flows through the circuit can be calculated using the equation V=IR, where V is the voltage of the battery, I is the current flowing through the circuit, and R is the resistance of the resistor.The student used a 2 ohm resistor and batteries of various voltages to obtain the results in Table 1. The currents shown in the table are NOT calculated using the formula V=IR, but instead directly measured from the circuit using an ammeter. It is important to note that the measured current will only exactly equal the calculated current if the system contains no internal resistance.Q.In Experiment 1, how much current is most likely flowing through the circuit?a)10 ampsb)1 ampsc)12 ampsd)5 ampsCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for A student was interested in determining the relationship between the current, voltage, and resistance in a direct circuit, such as those exemplified by batteries connected to light bulbs. The student built the circuit presented in Figure 1 using a 2 ohm resistor.The current that flows through the circuit can be calculated using the equation V=IR, where V is the voltage of the battery, I is the current flowing through the circuit, and R is the resistance of the resistor.The student used a 2 ohm resistor and batteries of various voltages to obtain the results in Table 1. The currents shown in the table are NOT calculated using the formula V=IR, but instead directly measured from the circuit using an ammeter. It is important to note that the measured current will only exactly equal the calculated current if the system contains no internal resistance.Q.In Experiment 1, how much current is most likely flowing through the circuit?a)10 ampsb)1 ampsc)12 ampsd)5 ampsCorrect answer is option 'D'. 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It is important to note that the measured current will only exactly equal the calculated current if the system contains no internal resistance.Q.In Experiment 1, how much current is most likely flowing through the circuit?a)10 ampsb)1 ampsc)12 ampsd)5 ampsCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A student was interested in determining the relationship between the current, voltage, and resistance in a direct circuit, such as those exemplified by batteries connected to light bulbs. The student built the circuit presented in Figure 1 using a 2 ohm resistor.The current that flows through the circuit can be calculated using the equation V=IR, where V is the voltage of the battery, I is the current flowing through the circuit, and R is the resistance of the resistor.The student used a 2 ohm resistor and batteries of various voltages to obtain the results in Table 1. The currents shown in the table are NOT calculated using the formula V=IR, but instead directly measured from the circuit using an ammeter. It is important to note that the measured current will only exactly equal the calculated current if the system contains no internal resistance.Q.In Experiment 1, how much current is most likely flowing through the circuit?a)10 ampsb)1 ampsc)12 ampsd)5 ampsCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice ACT tests.
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