Two trains one travelling at 15m/s and other at 20m/s are headed towards one another aling a straight track. Both the driver apply breakes simaltanaeously when they are 500m apart. If each train has a retardation of 1m/s , the separation after they stop a. 192.5m b. 225.5m c. 187.5m d. 155.5m?

Question

Answer

Answer:

Given, speed of first train = 15 m/s

Speed of second train = 20 m/s

Distance between two trains = 500 m

Retardation = 1 m/s

Step 1: Calculate the time taken by the trains to stop

We know that, retardation = (final velocity - initial velocity) / time

For both the trains, retardation = 1 m/s

Initial velocity of first train = 15 m/s

Final velocity of first train = 0 m/s

Initial velocity of second train = 20 m/s

Final velocity of second train = 0 m/s

Time taken by first train to stop = (15 - 0) / 1 = 15 seconds

Time taken by second train to stop = (20 - 0) / 1 = 20 seconds

Step 2: Calculate the distance covered by the trains before stopping

Distance covered by first train before stopping = (15 * 15) / (2 * 1) = 112.5 m

Distance covered by second train before stopping = (20 * 20) / (2 * 1) = 200 m

Step 3: Calculate the total distance covered by both the trains before stopping

Total distance covered by both the trains before stopping = 112.5 + 200 = 312.5 m

Step 4: Calculate the separation distance after they stop

Separation distance after they stop = Distance between two trains - Total distance covered by both the trains before stopping

Separation distance after they stop = 500 - 312.5 = 187.5 m

Therefore, the separation after they stop is 187.5m (Option C).

Answer

(C) 187.5 mUsing equations of stopping distance,After applying break train with velocity 15 travels distance [15]^2/(2)(1)= 112.5m Similarly, another train travels distance= [20]^2/(2)(1) = 200mSo, final separation= 500 - (112.5+200)                                  = 187.5 m

Answer

Plz.. solve it

Answer

187.5

Similar Class 11 Doubts

Two trains, one travelling at 90 m/s and the other travelling at 120 m/s, are moving towards each other on the same track. When they are 11 km apart, both drivers simultaneously apply brakes. If the brakes decelerate each train at the rate of 3m/s2 , then the distance travelled by the second train?

two projectiles are thrown from the same point simultaneously with same velocity 10m/s .one goes straight vertically while other at 60 degree with the vertical. what will be the distance of separation between the two after 1 second of their throw

two projectiles are thrown from the same point simultaneously with same velocity 10m/s .one goes straight vertically while other at 60 degree with the vertical. what will be the distance of separation between the two after 1 second of their throw.

A train starts from rest from a station with acceleration 0.2m/s^2 on a straight track and then comes to rest after attaining maximum speed on another station due to retardation 0.4m/s^2. If total time spent is half an hour, then distance between two stations is (neglect length of train)?

Top Courses for Class 11View all

Chemistry Class 11

CUET Mock Test Series

English Class 11

Chemistry Practice Tests: CUET Preparation

CUET Mock Test: Humanities Subjects 2025

Top Courses for Class 11

Top Courses for Class 11

Suggested Free Tests

Related Content

Schools

Competitive Examinations

Quick Access Links

Technical Exams