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Given the vertices of parallelogram QRST in the standard (x, y) coordinate plane below, what is the area of triangle QRS, in square units?
- a)24
- b)28
- c)48
- d)60
- e)80
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Given the vertices of parallelogram QRST in the standard (x, y) coordi...
Remember that the area of a parallelogram is equal to base × height. In this case, the base is [3 − (−3)] or [2 − (−4)], both of which equal 6, and the height is (3 − (−5)) = 8.
Thus the area is 6 × 8 = 48. The area of triangle QRS,
is half the area of the parallelogram, or 24.
Thus the area is 6 × 8 = 48. The area of triangle QRS,
is half the area of the parallelogram, or 24.Most Upvoted Answer
Given the vertices of parallelogram QRST in the standard (x, y) coordi...
Remember that the area of a parallelogram is equal to base × height. In this case, the base is [3 − (−3)] or [2 − (−4)], both of which equal 6, and the height is (3 − (−5)) = 8.
Thus the area is 6 × 8 = 48. The area of triangle QRS, is half the area of the parallelogram, or 24.
Thus the area is 6 × 8 = 48. The area of triangle QRS,
is half the area of the parallelogram, or 24.
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Given the vertices of parallelogram QRST in the standard (x, y) coordinate plane below, what is the area of triangle QRS, in square units?a)24b)28c)48d)60e)80Correct answer is option 'A'. Can you explain this answer?
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