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In the standard (x, y) coordinate plane below, the points (0,2), (8,2), (3,6), and (11,6) are the vertices of a parallelogram. What is the area, in square units, of the parallelogram?
  • a)
    6√2
  • b)
    16
  • c)
    32
  • d)
    56
  • e)
    88
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
In the standard (x, y) coordinate plane below, the points (0,2), (8,2)...
The area of a parallelogram is bh, where b is the length of the base and h is the height perpendicular to the bases. The length of the base can be determined by subtracting the x-coordinates of the points that determine the bases: 8 - 0 = 11 - 3 = 8 units long. The height, since it is the height perpendicular to the bases, can be determined by subtracting the y-coordinates of the points: 6 - 2 = 4. Therefore the area is bh = (8)(4), or 32.
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In the standard (x, y) coordinate plane below, the points (0,2), (8,2), (3,6), and (11,6) are the vertices of a parallelogram. What is the area, in square units, of the parallelogram?a)6√2b)16c)32d)56e)88Correct answer is option 'C'. Can you explain this answer?
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