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Suppose k it is any integer such that the equation 2x2 + kx + 5 = 0 has no real roots and the equation x2 + (k − 5)x + 1 = 0 has two distinct real roots for x. Then, the number of possible values of k is
  • a)
    9
  • b)
    13
  • c)
    8
  • d)
    7
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Suppose k it is any integer such that the equation 2x2 + kx + 5 = 0 ha...
If the equation 2x^2 + kx + 5 = 0 has no real roots, then the discriminant must be negative.

The discriminant is given by b^2 - 4ac, where a = 2, b = k, and c = 5.

So, we have k^2 - 4(2)(5) < />

Simplifying, we get k^2 - 40 < />

Adding 40 to both sides, we have k^2 < />

Taking the square root of both sides (remembering that k is an integer), we get -√40 < k="" />< />

This can be further simplified to -2√10 < k="" />< />

Therefore, the possible values of k are all integers between -2√10 and 2√10, excluding -2√10 and 2√10.
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Suppose k it is any integer such that the equation 2x2 + kx + 5 = 0 has no real roots and the equation x2 + (k − 5)x + 1 = 0 has two distinct real roots for x. Then, the number of possible values of k isa)9b)13c)8d)7Correct answer is option 'A'. Can you explain this answer?
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