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Suppose k is any integer such that the equation 2x2 + kx + 5 = 0 has no real roots and the equation x2 + (k - 5)x + 1 = 0 has two distinct real roots for x. Then, the number of possible values of k is
  • a)
    9
  • b)
    7
  • c)
    8
  • d)
    13
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Suppose k is any integer such that the equation 2x2 + kx + 5 = 0 has n...
2x2 + kx + 5 = 0 has no real roots so D < 0
k2 −40 < 0

x2 + (k − 5)x + 1 = 0 has two distinct real roots so D > 0

Therefore possibe value of k are -6, -5, -4, -3, -2, -1, 0, 1, 2
In 9 total 9 integer values of k are possible.
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Suppose k is any integer such that the equation 2x2 + kx + 5 = 0 has no real roots and the equation x2 + (k - 5)x + 1 = 0 has two distinct real roots for x. Then, the number of possible values of k isa)9b)7c)8d)13Correct answer is option 'A'. Can you explain this answer?
Question Description
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