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Two dice are thrown simultaneously. The probability that at least one of them will have 6 facing up is
- a)1/36
- b)1/3
- c)25/36
- d)11/36
Correct answer is option 'D'. Can you explain this answer?
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Two dice are thrown simultaneously. The probability that at least one ...
P(atleast one of dice will have 6 facing
= 1 - P(none of dice have 6 facing up)
= 1 - P(none of dice have 6 facing up)
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Two dice are thrown simultaneously. The probability that at least one ...
Probability of at least one 6 facing up
Probability can be calculated by determining the total number of favorable outcomes and then dividing by the total number of possible outcomes.
Determining the total number of possible outcomes
- When two dice are thrown simultaneously, each die has 6 faces.
- Therefore, the total number of possible outcomes when throwing two dice is 6 x 6 = 36.
Determining the number of favorable outcomes
- To find the number of outcomes where at least one die shows a 6, we can calculate the outcomes where no 6 appears and subtract that from the total outcomes.
- The outcomes where no 6 appears on either die are when both dice show numbers other than 6. This can be calculated as 5 x 5 = 25 outcomes.
- Therefore, the number of favorable outcomes where at least one die shows a 6 is 36 - 25 = 11 outcomes.
Calculating the probability
- The probability of at least one die showing a 6 is the number of favorable outcomes divided by the total number of possible outcomes.
- Probability = Number of favorable outcomes / Total number of possible outcomes
- Probability = 11/36
Therefore, the correct answer is option 'D' which is 11/36.
Probability can be calculated by determining the total number of favorable outcomes and then dividing by the total number of possible outcomes.
Determining the total number of possible outcomes
- When two dice are thrown simultaneously, each die has 6 faces.
- Therefore, the total number of possible outcomes when throwing two dice is 6 x 6 = 36.
Determining the number of favorable outcomes
- To find the number of outcomes where at least one die shows a 6, we can calculate the outcomes where no 6 appears and subtract that from the total outcomes.
- The outcomes where no 6 appears on either die are when both dice show numbers other than 6. This can be calculated as 5 x 5 = 25 outcomes.
- Therefore, the number of favorable outcomes where at least one die shows a 6 is 36 - 25 = 11 outcomes.
Calculating the probability
- The probability of at least one die showing a 6 is the number of favorable outcomes divided by the total number of possible outcomes.
- Probability = Number of favorable outcomes / Total number of possible outcomes
- Probability = 11/36
Therefore, the correct answer is option 'D' which is 11/36.
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Two dice are thrown simultaneously. The probability that at least one of them will have 6 facing up isa)1/36b)1/3c)25/36d)11/36Correct answer is option 'D'. Can you explain this answer?
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