Electrical Engineering (EE) Exam > Electrical Engineering (EE) Questions > An amplifier has a standard spot noise figure...
Start Learning for Free
An amplifier has a standard spot noise figure F0 = 6.31 (8.0 dB). The amplifier, that is used to amplify the output of an antenna have antenna temperature of Ta = 180 K
Q. The effective input noise temperature of this amplifier is
- a)2520 K
- b)2120 K
- c)2710 K
- d)1540 K
Correct answer is option 'D'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
An amplifier has a standard spot noise figure F0 =6.31 (8.0 dB). The a...
The effective input noise temperature of an amplifier can be calculated using the formula:
Te = (To + (F - 1) * Ta)
Where:
Te is the effective input noise temperature
To is the reference noise temperature (usually 290 K)
F is the noise figure in linear scale
Ta is the antenna temperature
Given:
F0 = 6.31 (8.0 dB)
Ta = 180 K
We need to convert the noise figure from logarithmic scale (dB) to linear scale (F). The conversion formula is:
F = 10^(F0/10)
Substituting the given value of F0:
F = 10^(8.0/10)
F = 10^0.8
F ≈ 6.31
Now we can calculate the effective input noise temperature:
Te = (To + (F - 1) * Ta)
Te = (290 + (6.31 - 1) * 180)
Te = (290 + 5.31 * 180)
Te = (290 + 957.18)
Te ≈ 1247 K
Therefore, the effective input noise temperature of this amplifier is approximately 1247 K. However, none of the given options match this calculation. Hence, there might be a mistake in the options provided.
Te = (To + (F - 1) * Ta)
Where:
Te is the effective input noise temperature
To is the reference noise temperature (usually 290 K)
F is the noise figure in linear scale
Ta is the antenna temperature
Given:
F0 = 6.31 (8.0 dB)
Ta = 180 K
We need to convert the noise figure from logarithmic scale (dB) to linear scale (F). The conversion formula is:
F = 10^(F0/10)
Substituting the given value of F0:
F = 10^(8.0/10)
F = 10^0.8
F ≈ 6.31
Now we can calculate the effective input noise temperature:
Te = (To + (F - 1) * Ta)
Te = (290 + (6.31 - 1) * 180)
Te = (290 + 5.31 * 180)
Te = (290 + 957.18)
Te ≈ 1247 K
Therefore, the effective input noise temperature of this amplifier is approximately 1247 K. However, none of the given options match this calculation. Hence, there might be a mistake in the options provided.
Free Test
FREE
| Start Free Test |
Community Answer
An amplifier has a standard spot noise figure F0 =6.31 (8.0 dB). The a...
Attention Electrical Engineering (EE) Students!
To make sure you are not studying endlessly, EduRev has designed Electrical Engineering (EE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Electrical Engineering (EE).
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Similar Electrical Engineering (EE) Doubts
Top Courses for Electrical Engineering (EE)View all
An amplifier has a standard spot noise figure F0 =6.31 (8.0 dB). The amplifier, that is used to amplify the output of an antenna have antenna temperature of Ta= 180 KQ. The effective input noise temperature of this amplifier isa)2520 Kb)2120 Kc)2710 Kd)1540 KCorrect answer is option 'D'. Can you explain this answer?
Question Description
An amplifier has a standard spot noise figure F0 =6.31 (8.0 dB). The amplifier, that is used to amplify the output of an antenna have antenna temperature of Ta= 180 KQ. The effective input noise temperature of this amplifier isa)2520 Kb)2120 Kc)2710 Kd)1540 KCorrect answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about An amplifier has a standard spot noise figure F0 =6.31 (8.0 dB). The amplifier, that is used to amplify the output of an antenna have antenna temperature of Ta= 180 KQ. The effective input noise temperature of this amplifier isa)2520 Kb)2120 Kc)2710 Kd)1540 KCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An amplifier has a standard spot noise figure F0 =6.31 (8.0 dB). The amplifier, that is used to amplify the output of an antenna have antenna temperature of Ta= 180 KQ. The effective input noise temperature of this amplifier isa)2520 Kb)2120 Kc)2710 Kd)1540 KCorrect answer is option 'D'. Can you explain this answer?.
An amplifier has a standard spot noise figure F0 =6.31 (8.0 dB). The amplifier, that is used to amplify the output of an antenna have antenna temperature of Ta= 180 KQ. The effective input noise temperature of this amplifier isa)2520 Kb)2120 Kc)2710 Kd)1540 KCorrect answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about An amplifier has a standard spot noise figure F0 =6.31 (8.0 dB). The amplifier, that is used to amplify the output of an antenna have antenna temperature of Ta= 180 KQ. The effective input noise temperature of this amplifier isa)2520 Kb)2120 Kc)2710 Kd)1540 KCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An amplifier has a standard spot noise figure F0 =6.31 (8.0 dB). The amplifier, that is used to amplify the output of an antenna have antenna temperature of Ta= 180 KQ. The effective input noise temperature of this amplifier isa)2520 Kb)2120 Kc)2710 Kd)1540 KCorrect answer is option 'D'. Can you explain this answer?.
Solutions for An amplifier has a standard spot noise figure F0 =6.31 (8.0 dB). The amplifier, that is used to amplify the output of an antenna have antenna temperature of Ta= 180 KQ. The effective input noise temperature of this amplifier isa)2520 Kb)2120 Kc)2710 Kd)1540 KCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE).
Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.
Here you can find the meaning of An amplifier has a standard spot noise figure F0 =6.31 (8.0 dB). The amplifier, that is used to amplify the output of an antenna have antenna temperature of Ta= 180 KQ. The effective input noise temperature of this amplifier isa)2520 Kb)2120 Kc)2710 Kd)1540 KCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
An amplifier has a standard spot noise figure F0 =6.31 (8.0 dB). The amplifier, that is used to amplify the output of an antenna have antenna temperature of Ta= 180 KQ. The effective input noise temperature of this amplifier isa)2520 Kb)2120 Kc)2710 Kd)1540 KCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for An amplifier has a standard spot noise figure F0 =6.31 (8.0 dB). The amplifier, that is used to amplify the output of an antenna have antenna temperature of Ta= 180 KQ. The effective input noise temperature of this amplifier isa)2520 Kb)2120 Kc)2710 Kd)1540 KCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of An amplifier has a standard spot noise figure F0 =6.31 (8.0 dB). The amplifier, that is used to amplify the output of an antenna have antenna temperature of Ta= 180 KQ. The effective input noise temperature of this amplifier isa)2520 Kb)2120 Kc)2710 Kd)1540 KCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice An amplifier has a standard spot noise figure F0 =6.31 (8.0 dB). The amplifier, that is used to amplify the output of an antenna have antenna temperature of Ta= 180 KQ. The effective input noise temperature of this amplifier isa)2520 Kb)2120 Kc)2710 Kd)1540 KCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice Electrical Engineering (EE) tests.
|
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup