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Which of the following is not a valid C variable name?
  • a)
    int number;
  • b)
    float rate;
  • c)
    int variable_count;
  • d)
    int $main;
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
Which of the following is not a valid C variable name?a)int number;b)f...
Invalid C Variable Name

The correct answer is option 'D' - int $main.

Explanation:
In C programming, variable names must follow certain rules and conventions in order to be valid. Let's analyze each option to understand why option 'D' is not a valid variable name.

1. int number:
- The variable name "number" is a valid C variable name.
- It starts with a lowercase letter and consists of only letters, numbers, and underscores.
- Therefore, option 'A' is a valid variable name.

2. float rate:
- The variable name "rate" is a valid C variable name.
- It starts with a lowercase letter and consists of only letters, numbers, and underscores.
- Therefore, option 'B' is a valid variable name.

3. int variable_count:
- The variable name "variable_count" is a valid C variable name.
- It starts with a lowercase letter and consists of only letters, numbers, and underscores.
- Therefore, option 'C' is a valid variable name.

4. int $main:
- The variable name "$main" is not a valid C variable name.
- C programming language does not allow variable names to start with special characters like '$'.
- Therefore, option 'D' is not a valid variable name.

Conclusion:
From the given options, option 'D' (int $main) is not a valid C variable name because it starts with a special character ('$'), which is not allowed in C programming.
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Community Answer
Which of the following is not a valid C variable name?a)int number;b)f...
Since only underscore and no other special character is allowed in a variable name, it results in an error.
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Which of the following is not a valid C variable name?a)int number;b)float rate;c)int variable_count;d)int $main;Correct answer is option 'D'. Can you explain this answer?
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