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If the letters of word DAUGHTER are to be arranged so that vowel occupy the odd places then number of different words are?
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If the letters of word DAUGHTER are to be arranged so that vowel occup...
There are 8 letters in the word daughter of which 3 are vowels and 5 are consonants. Again, there are 4 odd places viz 1st, 3rd,5th & 7th and 4 even places viz. 2nd, 4th, 6th & 8th. Now, in 4 odd places 3 vowels can be put in 4P3 = 24 ways. Having fixed up the vowels in 4 odd places, we are left with 5 places viz 1 odd and 4 even places. In these 5 places we have to fix 5 consonants which can be done in 5P5 = 5! = 120 ways. Hence, total number of arrangements (or words) will be = 24 x 120 = 2880.
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If the letters of word DAUGHTER are to be arranged so that vowel occupy the odd places then number of different words are?
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