First, let's understand the reaction between silver nitrate (AgNO3) and the compounds given to determine whether a white precipitate will form or not.

AgNO3 is a soluble salt, and when it is mixed with a compound that contains chloride ions (Cl-), a white precipitate of silver chloride (AgCl) is expected to form. This reaction can be represented as follows:

AgNO3 + Cl- → AgCl (white precipitate) + NO3-

Now, let's analyze each compound individually to determine whether a white precipitate will form or not.

1. PtCl4.4NH3:
This compound contains chloride ions (Cl-) from the PtCl4 part. Therefore, when it reacts with AgNO3, a white precipitate of AgCl is expected to form.

2. COCl3.3NH3:
This compound does not contain any chloride ions (Cl-), so it will not react with AgNO3 to form a white precipitate. Instead, it will remain as is.

3. Impure chloroform:
Chloroform (CHCl3) contains chloride ions (Cl-), and therefore, impure chloroform may also contain chloride ions. When it reacts with AgNO3, a white precipitate of AgCl is expected to form.

4. Carnelite:
Carnelite is a mineral with the chemical formula KMgCl3·6H2O. It contains chloride ions (Cl-) from the MgCl3 part. Therefore, when it reacts with AgNO3, a white precipitate of AgCl is expected to form.

5. Vinyl chloride:
Vinyl chloride (C2H3Cl) does not contain any chloride ions (Cl-), so it will not react with AgNO3 to form a white precipitate. Instead, it will remain as is.

In summary, compounds 1, 3, and 4 are expected to yield a white precipitate with AgNO3 solution because they contain chloride ions (Cl-). Compound 2 does not contain chloride ions, and compound 5 also does not have any chloride ions.