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4 A single-phase 440/110 V transformer has primary and secondary winding resistance of 0.3 Q and 0.02 Q, respectively. If iron loss on normal input voltage is 150 W, a. calculate the secondary current at which maximum efficiency will occur. b. What is the value of this maximum efficiency for unity power factor load?
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4 A single-phase 440/110 V transformer has primary and secondary windi...
a. Calculation of Secondary Current at Maximum Efficiency
To find the secondary current at which maximum efficiency occurs, we need to determine the equivalent resistance of the transformer. The equivalent resistance is the sum of the primary and secondary winding resistances.
Given:
Primary winding resistance (R1) = 0.3 Q
Secondary winding resistance (R2) = 0.02 Q
The equivalent resistance (Req) can be calculated as:
Req = R1 + R2
= 0.3 Q + 0.02 Q
= 0.32 Q
The maximum efficiency occurs when the copper loss is equal to the iron loss. The copper loss (Pcu) can be calculated as the square of the secondary current (I2) multiplied by the equivalent resistance (Req).
Pcu = I2^2 * Req
The iron loss (Piron) is given as 150 W.
At maximum efficiency, Pcu = Piron.
Therefore, we can write the equation as:
I2^2 * Req = Piron
I2^2 * 0.32 Q = 150 W
Solving the equation, we can find the value of I2.
b. Value of Maximum Efficiency for Unity Power Factor Load
The maximum efficiency (ηmax) is given by the formula:
ηmax = (Pout / Pin) * 100
Where Pout is the output power and Pin is the input power.
For a unity power factor load, the output power (Pout) is equal to the input power (Pin). Hence, the maximum efficiency for a unity power factor load is 100%.
Explanation:
- The secondary current at which maximum efficiency occurs is calculated by equating the copper loss to the iron loss.
- The equivalent resistance of the transformer is the sum of the primary and secondary winding resistances.
- The maximum efficiency is the ratio of output power to input power, multiplied by 100.
- For a unity power factor load, the output power is equal to the input power, resulting in a maximum efficiency of 100%.
To find the secondary current at which maximum efficiency occurs, we need to determine the equivalent resistance of the transformer. The equivalent resistance is the sum of the primary and secondary winding resistances.
Given:
Primary winding resistance (R1) = 0.3 Q
Secondary winding resistance (R2) = 0.02 Q
The equivalent resistance (Req) can be calculated as:
Req = R1 + R2
= 0.3 Q + 0.02 Q
= 0.32 Q
The maximum efficiency occurs when the copper loss is equal to the iron loss. The copper loss (Pcu) can be calculated as the square of the secondary current (I2) multiplied by the equivalent resistance (Req).
Pcu = I2^2 * Req
The iron loss (Piron) is given as 150 W.
At maximum efficiency, Pcu = Piron.
Therefore, we can write the equation as:
I2^2 * Req = Piron
I2^2 * 0.32 Q = 150 W
Solving the equation, we can find the value of I2.
b. Value of Maximum Efficiency for Unity Power Factor Load
The maximum efficiency (ηmax) is given by the formula:
ηmax = (Pout / Pin) * 100
Where Pout is the output power and Pin is the input power.
For a unity power factor load, the output power (Pout) is equal to the input power (Pin). Hence, the maximum efficiency for a unity power factor load is 100%.
Explanation:
- The secondary current at which maximum efficiency occurs is calculated by equating the copper loss to the iron loss.
- The equivalent resistance of the transformer is the sum of the primary and secondary winding resistances.
- The maximum efficiency is the ratio of output power to input power, multiplied by 100.
- For a unity power factor load, the output power is equal to the input power, resulting in a maximum efficiency of 100%.
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4 A single-phase 440/110 V transformer has primary and secondary winding resistance of 0.3 Q and 0.02 Q, respectively. If iron loss on normal input voltage is 150 W, a. calculate the secondary current at which maximum efficiency will occur. b. What is the value of this maximum efficiency for unity power factor load?
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4 A single-phase 440/110 V transformer has primary and secondary winding resistance of 0.3 Q and 0.02 Q, respectively. If iron loss on normal input voltage is 150 W, a. calculate the secondary current at which maximum efficiency will occur. b. What is the value of this maximum efficiency for unity power factor load? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about 4 A single-phase 440/110 V transformer has primary and secondary winding resistance of 0.3 Q and 0.02 Q, respectively. If iron loss on normal input voltage is 150 W, a. calculate the secondary current at which maximum efficiency will occur. b. What is the value of this maximum efficiency for unity power factor load? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 4 A single-phase 440/110 V transformer has primary and secondary winding resistance of 0.3 Q and 0.02 Q, respectively. If iron loss on normal input voltage is 150 W, a. calculate the secondary current at which maximum efficiency will occur. b. What is the value of this maximum efficiency for unity power factor load?.
4 A single-phase 440/110 V transformer has primary and secondary winding resistance of 0.3 Q and 0.02 Q, respectively. If iron loss on normal input voltage is 150 W, a. calculate the secondary current at which maximum efficiency will occur. b. What is the value of this maximum efficiency for unity power factor load? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about 4 A single-phase 440/110 V transformer has primary and secondary winding resistance of 0.3 Q and 0.02 Q, respectively. If iron loss on normal input voltage is 150 W, a. calculate the secondary current at which maximum efficiency will occur. b. What is the value of this maximum efficiency for unity power factor load? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 4 A single-phase 440/110 V transformer has primary and secondary winding resistance of 0.3 Q and 0.02 Q, respectively. If iron loss on normal input voltage is 150 W, a. calculate the secondary current at which maximum efficiency will occur. b. What is the value of this maximum efficiency for unity power factor load?.
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