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The normal equations for a straight line y = ax + b are:a)Σy = aΣx + nb and Σxy = aΣx2 + bΣxb)Σxy = aΣx + nb and Σy = aΣx2 + bΣxc)Σy = aΣx + nb and Σxy = aΣx2 + bΣxyd)Σy = aΣx + nb and Σx2y = aΣx2 + bΣxCorrect answer is option 'A'. Can you explain this answer? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about The normal equations for a straight line y = ax + b are:a)Σy = aΣx + nb and Σxy = aΣx2 + bΣxb)Σxy = aΣx + nb and Σy = aΣx2 + bΣxc)Σy = aΣx + nb and Σxy = aΣx2 + bΣxyd)Σy = aΣx + nb and Σx2y = aΣx2 + bΣxCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The normal equations for a straight line y = ax + b are:a)Σy = aΣx + nb and Σxy = aΣx2 + bΣxb)Σxy = aΣx + nb and Σy = aΣx2 + bΣxc)Σy = aΣx + nb and Σxy = aΣx2 + bΣxyd)Σy = aΣx + nb and Σx2y = aΣx2 + bΣxCorrect answer is option 'A'. Can you explain this answer?.

Solutions for The normal equations for a straight line y = ax + b are:a)Σy = aΣx + nb and Σxy = aΣx2 + bΣxb)Σxy = aΣx + nb and Σy = aΣx2 + bΣxc)Σy = aΣx + nb and Σxy = aΣx2 + bΣxyd)Σy = aΣx + nb and Σx2y = aΣx2 + bΣxCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Civil Engineering (CE). Download more important topics, notes, lectures and mock test series for Civil Engineering (CE) Exam by signing up for free.

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